Finding general and special solutions of differential equations The general solution of 1. Y '= 2x 2. The special solution of differential equation y '= e ^ X-Y satisfying Y / x = 1 = 1 + LN2 is Ay=ln(e^x+1) b y=ln(e^x+2) c y=ln(e^x+e); d y=x+ln2

Finding general and special solutions of differential equations The general solution of 1. Y '= 2x 2. The special solution of differential equation y '= e ^ X-Y satisfying Y / x = 1 = 1 + LN2 is Ay=ln(e^x+1) b y=ln(e^x+2) c y=ln(e^x+e); d y=x+ln2

1, the general solution is x ^ 2 + C, (C is any constant)
2. First of all, make the solution satisfy the differential equation, find out the general solution, and then let y (1) = 1 + LN2, find out C