Let f (x) be differentiable at x0, then it is equal to Why Lim f (x + H) - f (X-H) / h = 2F '(x) Why 2F '(x), not 1 / 2 F' (x) F '(x) isn't that 2 in the denominator, and it becomes 1 / 2 after it is put forward?

Let f (x) be differentiable at x0, then it is equal to Why Lim f (x + H) - f (X-H) / h = 2F '(x) Why 2F '(x), not 1 / 2 F' (x) F '(x) isn't that 2 in the denominator, and it becomes 1 / 2 after it is put forward?

Faint, the denominator put more than 2, of course, one more 2 molecules