If f (x) = (AX + 1) (x + a) is an odd function, what is f (2) equal to

If f (x) = (AX + 1) (x + a) is an odd function, what is f (2) equal to

Since f (x) is an odd function, f (x) = - f (- x), i.e
f(x)+f(-x)=0
(ax+1)(x+a)+(-ax+1)(-x+a)=0
2a(x^2+1)=0
a=0
f(x)=x
f(2)=2