The limit x is close to 0.ln/tan 2x X is close to 0.ln/tan2x. Please write down the process. Thank you ~ ~ ~ I'm always wrong~~

The limit x is close to 0.ln/tan 2x X is close to 0.ln/tan2x. Please write down the process. Thank you ~ ~ ~ I'm always wrong~~

0 / 0 type limit
According to the law of lobita, the derivative can be obtained from the numerator and denominator
The original formula = {[2 / (1 + 2x)] / [2 / (cos2x) ^ 2]} (in X - > 0)
=(cos2x) ^ 2 / (2x + 1) (in X - > 0)
=1