Ln (1 + 2x) - what is the limit of sin3x? When x tends to 0, don't use the method of derivation

Ln (1 + 2x) - what is the limit of sin3x? When x tends to 0, don't use the method of derivation

We can use the equivalent infinitesimal.. sin3x ~ 3x ln (1 + 2x) ~ 2x, so the limit of Ln (1 + 2x) / sin3x is 2 / 3