When x tends to 1 +, limlnx · ln (x-1) Using the law of lobida

When x tends to 1 +, limlnx · ln (x-1) Using the law of lobida

First, transform it into the form of 0 / 0, that is LNX / (1 / ln (x-1)), and then use the law of lobita, it is easy to calculate the result as - ∞. The man upstairs happens to be right, and the method is wrong