Lim ln (1 + TaNx) / X when x tends to zero The existence criterion of limit and two important limits are used to solve the problem

Lim ln (1 + TaNx) / X when x tends to zero The existence criterion of limit and two important limits are used to solve the problem

lim [ln(1+tanx)]/x=lim [(tanx)/x] lim {ln(1+tanx)/tanx}=lim {ln(1+tanx)/tanx}
=lim [ln(1+tanx)^(1/tanx)]=lne=1