Given (sin α - 3-cos α) / (2 * sin α + 5 * cos α) = - 5, find Tan α

Given (sin α - 3-cos α) / (2 * sin α + 5 * cos α) = - 5, find Tan α

(sin α - 3-cos α) / (2 * sin α + 5 * cos α) = - 5 can be reduced to 11sin @ + 24cos @ = 3, and (sin @) ^ 2 + (COS @) ^ 2 = 1, then sin @, cos @, and Tan @