The image of function y = loga (X-2) - 2 passes through the fixed point (a > 0, a is not equal to 1) rt

The image of function y = loga (X-2) - 2 passes through the fixed point (a > 0, a is not equal to 1) rt

loga(1)=0
So let X-2 = 1
x=3
Then y = loga (1) - 2 = - 2
So the fixed point is (3, - 2)