If (sin α + cos α) / (sin α - cos α) = 2, find the value of sin (α - 5 π) sin (3 π / 2 - α)

If (sin α + cos α) / (sin α - cos α) = 2, find the value of sin (α - 5 π) sin (3 π / 2 - α)

∫ (sin α + cos α) / (sin α - cos α) = 2 = = > sin α + cos α = 2 (sin α - cos α) = = > sin α = 3cos α = = > (3cos α) ^ 2 + (COS α) ^ 2 = 1 = = > 10 (COS α) ^ 2 = 1 (COS α) ^ 2 = 1 / 10, so sin (α - 5 π) sin (3 π / 2 - α) = - sin α (- cos α) = sin α cos α = (3cos α) cos α = 3