Given that m and N are natural numbers and satisfy 168 + n square = m square, find m and n m. N is a natural number and satisfies 168 + M & # 178; = M & # 178;, find m and n

Given that m and N are natural numbers and satisfy 168 + n square = m square, find m and n m. N is a natural number and satisfies 168 + M & # 178; = M & # 178;, find m and n

∵168+n²=m²
∴m²-n²=168
∴(m+n)(m-n)=168
∴m-n=2 m-n=4 m-n=6 m-n=12
m+n=84 m+n=42 m+n=28 m+n=14
∴m=43 m=23 m= 17 m=13
n=41 n=19 n=11 n=1