X ^ 3 + y ^ 3-4ax ^ 2Y = 0 for derivative of implicit function

X ^ 3 + y ^ 3-4ax ^ 2Y = 0 for derivative of implicit function

The two sides are derived from X
3x^2+3y^2y'-8axy-4ax^2y'=0
y'=(3x^2-8axy)/(4ax^2-3y^2)

The addition and subtraction of rational numbers: 1-4 + 3-0.5, - 2.4 + 3.5-4.6 + 3.5, (- 7) - (+ 5) + (- 4) - (- 10),
3 / 4-2 / 7 + (- 1 / 6) - (- 2 / 3). We need to use the land equation and the law of combination of addition to write the land equation. 55555 prawns, please help me. Let's do these. School will start in a few days~

1-4+3-0.5=(1+3)+[-4+(-0.5)]=4+(-4.5)=-(4.5-4)=-0.5-2.4+3.5-4.6+3.5=[-2.4+(-4.6)]+(3.5+3.5)=-7+7=0(-7)-(+5)+(-4)-(-10)=(-7)+(-5)+(-4)+10=-16+10=-(16-10)=-63/4-2/7+(-1/6)-(-2/3)=3/4+(-2/7)+(-1/6)+2/3=(3...

Given that Tana and Tan (π / 4-A) are the two roots of the equation AX ^ 2 + BX + C = 0, then the relationship among a, B and C is?
A. B = a + C b.2b = a + C C.C = B + a D.C = AB better give me a little hint

Because the two roots of the equation AX ^ 2 + BX + C on Tana and Tan (π / 4-A) are known by Weida's theorem
tana+tan(π/4-a)=-b/a
tana*tan(π/4-a)=c/a
Then we know Tan (a + π / 4-A) = (Tana + Tan (π / 4-A)) / (1-tana * Tan (π / 4-A))
Then, we take the two formulas obtained by Weida formula into the above formula and get Tan (a + π / 4-A) = Tan (π / 4) = (- C / a) / (1-B / a)
We get 1-C / a = - B / A
Finally, it is reduced to a + B = C (a is not equal to 0)

How to make a round steel symbol (one circle, one vertical in the middle)
Sometimes there's a horizontal line down there

Φ
Sogou input method --- soft keyboard --- Greek alphabet --- upper key plus "V" key

Find ∫ ∫ y ^ 2D σ, where D is surrounded by an arch of cycloid x = a (t-sint), y = a (1-cost) (0 ≤ t ≤ 2 π) and X axis

First product y,
∫∫y²dσ
=∫[0---->2πa] dx∫[0--->y(x)] y²dy
=(1/3)∫[0---->2πa] y³(x) dx
Let x = a (t-sint), then y (x) = a (1-cost), DX = a (1-cost) DT, t: 0 --- > 2 π
=(1/3)∫[0---->2π] a⁴(1-cost)⁴ dt
=(a⁴/3)∫[0---->2π] (1-cost)⁴ dt
=(a⁴/3)∫[0---->2π] (1-4cost+6cos²t-4cos³t+cos⁴t) dt
Sum of squares to the fourth power
=(a⁴/3)∫[0---->2π] (1-4cost+3(1+cos2t)-4cos³t+(1/4)(1+cos2t)²) dt
=(a⁴/3)∫[0---->2π] (1-4cost+3(1+cos2t)-4cos³t+(1/4)(1+2cos2t+cos²2t)) dt
=(a⁴/3)∫[0---->2π] ((17/4)-4cost+(7/2)cos2t-4cos³t+(1/4)cos²2t) dt
Further power reduction
=(a⁴/3)∫[0---->2π] ((17/4)-4cost+(7/2)cos2t-4cos³t+(1/8)(1+cos4t)) dt
=(a⁴/3)∫[0---->2π] ((35/8)-4cost+(7/2)cos2t+(1/8)cos4t) dt-(4a⁴/3)∫[0---->2π] cos³t dt
=(a⁴/3)[(35/8)t-4sint+(7/4)sin2t+(1/32)sin4t]-(4a⁴/3)∫[0---->2π] cos²t d(sint)
=(a⁴/3)[(35/8)t-4sint+(7/4)sin2t+(1/32)sin4t]-(4a⁴/3)∫[0---->2π] (1-sin²t) d(sint)
=(a⁴/3)[(35/8)t-4sint+(7/4)sin2t+(1/32)sin4t]-(4a⁴/3)(sint-(1/3)sin³t |[0---->2π]
=(a⁴/3)*(35/8)*(2π)
=35πa⁴/12

How many kilometers is the distance between the two places? (equation solution: s fast - s slow = s poor or s a + S B = s total distance)

Let the distance between a and B be X,
X/10-X/15=2
Then x = 60

The focus of the ellipse is F1 (- 3,0) F2 (3,0) P, and the absolute value of F1F2 is the median of the absolute value of Pf1 and PF2
The equation of an ellipse

From the fact that the focus of the ellipse is F1 (- 3,0) F2 (3,0): C = 3
Because | Pf1 | + | PF2 | = 2A
And because: the absolute value of F1F2 is the median of the absolute value of Pf1 and PF2
So: | F1F2 | = 2C = (| Pf1 | + | PF2 |) / 2 = a
That is: a = 2C = 6
So: B ^ = a ^ 2-C ^ 2 = 36-9 = 27
So the elliptic equation is: x ^ 2 / 36 + y ^ 2 / 27 = 1
That's it,

Shanghai primary school fifth grade Chinese ＼ English ＼ mathematics exercise paper

Final test paper name___________ Score: 1. Fill in your satisfactory answer in brackets. (20 points) 1. 8.359 million writing (), rounding to 10000 places is about () 2. 1.75 hours = () hours () 7800 square meters = () square kilometers 3. Average 4 meters of wire

( x²+y²-10x-10y=0 ,x²+y²-6x+2y-40=0 )
Find x, y

First of all, we can get both
(X-5) square + (Y-5) square = 50
(x-3) square + (y + 1) square = 50
The left sides of the two formulas are equal, so they are simplified into one
x=10-3y
Substituting any one of the original equations, we get the following results:
X = 10, y = 0 or
X=-2,Y=4

Score mixed operation exercises and answers urgent to 50 questions

3/7 × 49/9 - 4/3 2.8/9 × 15/36 + 1/27 3.12× 5/6 – 2/9 ×3 4.8× 5/4 + 1/4 5.6÷ 3/8 – 3/8 ÷6 6.4/7 × 5/9 + 3/7 × 5/9 7.5/2 -（ 3/2 + 4/5 ） 8.7/8 + （ 1/8 + 1/9 ） 9.9 × 5/6 + 5/6 10.3/4 × 8...