The derivative of an implicit function needs to be derived on both sides of the equation. For example, the second step in the derivation of Y ^ 5 + 2y-x-3x ^ 7 = 0 is: 5Y ^ 4dy / DX + 2dy / dx-1-21x ^ 6 = 0. What is the principle?

The derivative of an implicit function needs to be derived on both sides of the equation. For example, the second step in the derivation of Y ^ 5 + 2y-x-3x ^ 7 = 0 is: 5Y ^ 4dy / DX + 2dy / dx-1-21x ^ 6 = 0. What is the principle?


Think of it this way,
The derivative of F (x) to X is f '(x),
Then the derivative of F (y) to X is f '(y) * dy / DX
Obviously here,
For y ^ 5 + 2y-x-3x ^ 7 = 0,
The derivative of Y ^ 5 is d (y ^ 5) / dy * dy / DX = 5Y ^ 4 * dy / DX
The derivative of 2Y is d (2Y) / dy * dy / DX = 2dy / DX
The derivative of X is 1, the derivative of 3x ^ 7 is 21x ^ 6
So we get the derivative
5y^4dy/dx+2dy/dx-1-21x^6=0



If the derivative of F (x) is equal to the quadratic function under the root, then f (x) is?


F (x) = (2x / 3 + C) to the power of 3 / 2



The radius of a sector is increased to three times of the original one, and the central angle of the sector is reduced to half of the original one
The radius of a sector is expanded three times, and its central angle is reduced to half. The area obtained is increased by 70 square centimeters
Area of


The original area is S1 = n π R & sup2; / 360
Now the area is S2 = 0.5N π (3R) & sup2; / 360 = 4.5n π R & sup2; / 360
The area of the new sector is 3.5 times larger than that of the original one
That is 3.5s1 = 70
Ψ S1 = 70 △ 3.5 = 20 square centimeter



How to observe the direction of resultant force and acceleration of simple harmonic motion


The resultant force direction and acceleration direction both point to the equilibrium position



Cut a piece of rectangular paper 96 cm in length and 80 cm in width into a square of the same size and as large as possible. After cutting, there is no surplus. How many pieces can be cut at least


The greatest common divisor of 96 and 80 is 16
So you can cut a square with a side length of 16 cm
96 has six sides
There are five sides of 80
A total of 6 * 5 = 30



There are two very simple physics problems, but I still can't do it. It's about the relationship between the displacement and time of uniform linear motion
The title is simplified
1. A helicopter stands still at point a in the air. At 10:56:40, it makes uniform acceleration and uniform motion along the horizontal direction from standstill. After accelerating in AB section, it enters into the uniform velocity zone of BC section. It passes through this position at 11:00. It is known that SAB = 5km and SBC = 10km
1. Find the velocity of BC segment
2. Calculate the acceleration of uniform acceleration motion in AB segment
It's due tomorrow


Let the acceleration be a, the acceleration is T seconds, and the maximum velocity is v;
Then v = at;
1/2*a*t^2=5000
at*(200-t)=10000
By comparing the two formulas, a can be eliminated and T = 100s can be calculated
a=1m/s^2.
Then the velocity of BC section is v = at = 100M / s;
The velocity of uniform acceleration in AB section is 1 m / S ^ 2



Given that the generatrix length of a cone is 6 & nbsp; cm and the radius of its bottom is 3cm, the center angle of the sector in the side expansion of the cone is calculated


The radius of the bottom of the cone is 3cm, the perimeter of the bottom of the cone is 6 π, let the center angle of the sector be n °, n π × 6180 = 6 π, and the solution is n = 180



1. Given that the length of line AB is 10 cm and the distances from point a and B to line L are 6 cm and 4 cm respectively, then the line L that meets the condition has ()
A. 1 B, 2 C, 3 D, 4
2. The following statement is correct ()
A. The line AB passes through the point a, B, the line a, B all pass through the point a
C. Line AB passes through point a D and line a passes through point a
Why do you do this?


1 C (the line AB is inclined up and down, and perpendicular to ab)
There is no graph or condition in question 2



The circumference of a semicircle is 30 or 84 meters. What are the radius and area of the semicircle?


The circumference of the semicircle is π R + 2R (R is the radius), which can be calculated by taking π = 3.14. The area of the semicircle is π (R ^ 2) / 2



If one side edge of a hexagonal prism is 5cm long, then the sum of all sides is 5cm______ .


∵ hexagonal prism has six edges, and the length of each edge is 5cm, ∵ the sum of all side edges = 6 × 5cm = 30cm