It is known that a + B + C = 0, then the value of a (1b + 1c) + B (1c + 1a) + C (1a + 1b) + 3 is______ ．

It is known that a + B + C = 0, then the value of a (1b + 1c) + B (1c + 1a) + C (1a + 1b) + 3 is______ ．

If a + B + C = 0, then a + B = -c, B + C = -a, a + C = -ba (1b + 1c) + B (1c + 1a) + C (1a + 1b) = a (a + B = -c, B + C = -a, a + B = -c, B + C = -a, a + C = -ba (BA (1b + 1c) + BA (1b + 1c) + B (1c + 1C (1c + 1A + 1a) + C (1a + 1A + 1b) + C (1a + 1B (1a + 1b + 1b) = a (a, B + B + CBC + B + B (B + B + C) and CAC, then a + B (a + B + B + B + B + B + B + C = 0), then a + B 3 + B 3 + B3 + C3 + C3 + C3 + C3 + C3 + C3 + C3 + C3 + C3 + C3 + C3 + C3 + C3 + C3 + C3 + C3 + C3 + C3 + C3 + C3 + C3 + C 3 = 3 AB C 〈 the original formula = - 3 + 3 = 0, so the answer is 0

Q: 1-2 + 3-4 + -14+15/-2+4-6+8…… +28-30=?
Simple calculation, please do not copy and paste

1-2+3-4+…… -14+15/-2+4-6+8…… +28-30
=[(1-2)+(3-4)+...+(13-14)+15]÷[(-2+4)+(-6+8)+...+(-26+28)-30]
=[(-1)×7+15]÷[2×7-30]
=8÷(-16)
=-1/2;
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