If a > 0, b > 0, ab ≥ 1 + A + B, then the minimum value of a + B is______

If a > 0, b > 0, ab ≥ 1 + A + B, then the minimum value of a + B is______

Therefore, the answer is 2 + 22

Xiaoning's family separated at 10:10 to catch the 11:00 train to travel. His family was 10km away from the railway station. They walked at 3km / h for 5 minutes to get to the bus station,
Then take a bus to the railway station. Suppose that the bus travels at least XKM per hour, they can not miss the train. Try to write the inequality that x should satisfy

I'll help you to be a good student
The inequality that x should satisfy: [10 km - 3 km / h × (5 / 60) H] / XKM ＜ (40-5) H
Finally, I wish you a higher level!

The basic inequality of the first grade of senior high school
If an object of mass a is placed on the tray of the balance, the mass of the right tray weight is mg. If an object of mass B is placed on the right tray of the balance, and the mass of the left tray is mg, the relationship between a + B and 2m is as follows

Let X be the length of the left arm and y be the length of the right arm
(1) AgX = mGy, that is AX = my;
(2) Bgy = MGX, that is, by = MX;
So a = my / x, B = MX / y, a + B = my / x + MX / Y;
Because y / x + X / Y > = 2 is constant;
So a + b > = 2m

The distance between a and B is 720 km. The passenger train and the train leave from the two places at the same time. They meet in 3.6 hours. The passenger train and the freight train leave each other
It's no use just asking for an answer. I want you to write out the process and write why beside it. Thank you for your cooperation!

First, calculate the speed of passenger car and freight car: 720 / 3.6 = 200 (km) per hour, then calculate the speed of passenger car and freight car: 200 * 3 / (3 + 2) = 120 (km) for passenger car and 200 * 2 / (3 + 2) = 80 (km) for freight car

Let a straight line with slope 2 pass through three points (3,5) (a, 7) (- 1, b) to find the values of real numbers a and B

According to the meaning of the title:
(7-5)/(a-3)=2 ===> 2/(a-3)=2 ===> a-3=1 ===> a=4
(b-5)/(-1-3)=2 ===> (b-5)/(-4)=2 ===> b-5=-8 ===> b=-3

There are two fire brigades a and B in a certain place, with a total of 336 people. Five seventh of the number of fire brigades a and three seventh of the number of fire brigades B are transferred, with a total of 188 people. There are two fire brigades a and B
How many people are there? Solve the equation

A x, then B 336-x
5/7x+3/7(336-x)=188
5/7x+336×3/7-3/7x=188
2/7x=188-144
2/7x=44
x=44×7/2
x=154
A: 154
B: 336-154 = 182

Today is Sunday. What day is it 100 days from today
It doesn't seem right. First look at the day of the week after 10 days. Look at the calendar

Today is Sunday, which is February 25, 2007
Ten days from today is Tuesday, March 06, 2007, the 17th day of the first lunar month
One hundred days from today is Monday, June 4, 2007, April 19 of the lunar calendar

A. The distance between B and B is 450 km. A and B start from a and B at the same time and travel in opposite directions. It is known that the speed of car a is 120 km / h and that of car B is 80 km. After how many hours, the distance between the two cars is 50 km?
Two methods: 1: not yet met 2: after meeting

1: We haven't met yet
(450-50) / (120 + 80) = 2 hours
2: After meeting
(450 + 50) / (120 + 80) = 2.5 hours

In triangle ABC, angle c = 90 degrees, angle a = 45 degrees, C = 18, a =?

Angle B = 45 degrees
So a = B
Use Pythagorean theorem. A + B = C
2A = C
So a = 9 √ 2

A car, B bike, along a road from a to B at the same time, the car 40 kilometers per hour, is 5 / 2 of the speed of the bicycle
Results what is the distance between a and B three hours earlier?

Let AB be x km away from each other
Vehicle speed = 40 km / h
Bicycle speed = 40 / (5 / 2) = 16 (km / h)
Then the time required for a to complete the whole journey = x / 40
Time for B to complete the whole journey = x / 16
X / 40 + 3 = x / 16
The solution is x = 80
A: AB is 80 kilometers apart