Y ^ 2 (x ^ 2-2x) ^ 3 + y ^ 2 factorization

Y ^ 2 (x ^ 2-2x) ^ 3 + y ^ 2 factorization

The original formula = y & # 178; [(X & # 178; - 2x) &# 179; + 1 & # 179;]
=y²[(x²-2x)+1][(x²-2x)²-(x²-2x)+1]
=y²(x-1)²(x^4-4x³+4x²-x²+2x+1)
=y²(x-1)²(x^4-4x³+3x²+2x+1)

Factorization: 2x ^ 4Y ^ 4-x ^ 8-y ^ 8

2x^4y^4-x^8-y^8
=-(x^8-2x^4y^4+y^8)
=-(x^4-y^4)^2
=-(x^2+y^2)^2(x+y)^2(x-y)^2

Factorization: (1) x ^ 2-4y ^ 2-2x + 1 (2) 9 (2x-y) ^ 2-6 (2x + y) + 1

(1) x^2-4y^2-2x+1
=(x-1)^2-4y^2
=(x-1+2y)(x-1-2y)
(2)9(2x-y)^2-6(2x+y)+1
={3(2x-y)-1}^2

The equation of a straight line passing through point a (4,1) with equal intercept on two coordinate axes is ()
A. X + y = 5B. X-Y = 5C. X + y = 5 or x-4y = 0d. X-Y = 5 or x + 4Y = 0

When the straight line passes through the origin, the slope is 14, and the equation of the straight line obtained from the point oblique formula is y = 14 & nbsp; X. when the straight line does not pass through the origin, let the equation of the straight line be: x + y = a, substituting point a (4,1) into the equation to get a = 5, and the equation of the straight line is x + y = 5. In conclusion, the equation of the straight line is y = 14 & nbsp; X or x + y = 5

How to read the English words of 213450?
How much is it

twenty-first
thirties
forties
fifties

Finding the power series expansion of function

The derivative can be solved first, then the derivative can be expanded by equal ratio series, and the series of the original function can be solved by term by term integration
arctan[(4+x^2)/(4-x^2)] '
=1/{1+[(4+x^2)/(4-x^2)]^2} * [(4+x^2)/(4-x^2)] '
Finally, it is simplified
=16x / (2x^4+32)
(please help to check whether the calculation is correct. I only write ideas, but I can't guarantee the calculation.)
Divide up and down by 32 at the same time
=(x/2) / [1+(x^4)/16]
This is a series with the first term x / 2 and the common ratio - (x ^ 4) / 16, so
=(x/2) * {1 - (x^4)/16 + [(x^4)/16]^2 - [(x^4)/16]^3 +...}
= x/2 - (x/2)^5 + (x/2)^9 - (x/2)^13 + ...
=∑(n=0,∞) [(-1)^n] * [(x/2)^(1+4n)]
I'm integrating this equation
The series expansion of the original formula is:
=∑(n=0,∞) [(-1)^n] * [1/(1+2n)] * [(x/2)^(2+4n)]

How much is 52 times 7

52 * 7 is about 350
50*7=350

Let f (x) be an odd function defined on R with a period of 3. If f (2) = 1, f (1) = a, then a = ()

Analysis: the periodic function f (x + T) = f (x), t is the period
According to the problem: F (x + 3K) = f (x), that is, f (1) = f (3-2) = f (- 2) = - f (2) = - 1
Commentary: periodic function, see the integer times of the period can be directly removed, at the same time, you can also fill in. Mathematically, there are more matching, that is to understand and think through, mathematics must think through

What is the difference between the reciprocal of 2 and the sum of 1 / 2 divided by the quotient of 1 / 2, minus the quotient of 0.5 divided by 1 / 4?
arithmetic

Sorry, wrong number. The difference is 0
The reciprocal of 2 is 1 / 2, (1 / 2 + 1 / 2) = 1, 1 divided by 1 / 2 equals 2, 0.5 divided by 1 / 4 = 2, so it is equal to 0

If the polynomial (x ^ 4 + x ^ 3 + 2x ^ 2-3x + 2) - (AX ^ 3-3x ^ 2 + BX + 1) does not contain x ^ 3 and X terms

(x^4+x^3+2x^2-3x+2)-(ax^3-3x^2+bx+1)
=x^4+(1-a)x³+5x²-(3+b)x+1
Does not contain x ^ 3 and X items
∴1-a=0
3+b=0
∴a=1
b=-3