If Z1 = a + bi (a, B ∈ R, ab ≠ 0), Z2 = a-bi, O is the coordinate origin, and the complex Z corresponds to the point Z, then the shape of △ z1oz2 2. A is a known real number, and the real numbers x and y satisfy a ^ 2 + (2 + I) a + 2XY + (X-Y) I = 0, then the trajectory of point (x, y) is

If Z1 = a + bi (a, B ∈ R, ab ≠ 0), Z2 = a-bi, O is the coordinate origin, and the complex Z corresponds to the point Z, then the shape of △ z1oz2 2. A is a known real number, and the real numbers x and y satisfy a ^ 2 + (2 + I) a + 2XY + (X-Y) I = 0, then the trajectory of point (x, y) is

|The shape of Z1 | = √ (a ^ 2 + B ^ 2) | Z2 | = √ (a ^ 2 + B ^ 2) | Z1 | = | Z2 | △ z1oz2 is isosceles triangle (2) a ^ 2 + (2 + I) a + 2XY + (X-Y) I = 0, which is transformed into complex form to get [a ^ 2 + 2A + 2XY] + [a + X-Y] I = 0, complex number = 0, real part a ^ 2 + 2A + 2XY = 0, imaginary part a + X-Y = 0A = Y-X, which is substituted into a ^ 2 + 2A + 2XY = 0

If Z1 = - 2 + I, Z2 = - 1 + 2I, then Z1 / Z2 =?

z1/z2=-(2-i)/[-(1-2i)]
=(2-i)(1+2i)/(1+4)
=(2-i+4i+2)/5
=(4+3i)/5
=4/5+3i/5.

Simple operation of 48 × 4 + 52 × 4

4*（48+52）=400

In triangle ABC, ab = AC, angle a = 36 degrees. BD is the bisector of angle ABC. Is triangle ABC similar to triangle BDC? Explain the reason and process
Urgent need

Because BD is the bisector of angle ABC, angle DBC = angle abd = 36 degrees
Because AB = AC, the angle BCD = angle ABC = 72 degrees
So the two triangles are similar

A is not equal to B, AB is not equal to 0, compare the size of (A4 + B4) (A2 + B2) and (A3 + B3) 2
Urgent! Please write the detailed process
thank you

A trapezoid has an upper bottom of 5 cm, a lower bottom of 8.2 cm and a height of 4.5 cm. If the largest triangle is cut out of the trapezoid, how many square centimeters is the remaining area?

To cut the largest triangle, the bottom of the trapezoid must be the bottom of the triangle, and the height of the trapezoid must be the height of the triangle, so the area of the triangle: 8.2 × 4.5 △ 2 = 18.45 (square centimeter), the area of the trapezoid: (5 + 8.2) × 4.5 △ 2 = 29.7 (square centimeter), and the remaining area: 29.7-18.45 = 11.25 (square centimeter). Answer: the remaining area is 11.25 square centimeter

If the function f (x) = LG (x (X-2 / 3) + 1) x belongs to the closed interval of 1,3 / 2, then the maximum value of F (x) is

True number = x & # 178; - 2x / 3 + 1
=(x-1/3)²+8/9
Axis of symmetry x = 1 / 3, opening upward
one

A snail, climbing a tree 9m high, rises 1m during the day and declines 2 / 3M at night. It starts to climb up one morning and reaches the top of the tree after how many days?
Is the view that (tree height - rising in the daytime) / (rising in the daytime - falling at night) = days right,
It seems to be (tree height - rising in the day) + (rising in the day - falling in the night) + 1——

9-1 = 8M
8 (1-2 / 3) = 24 days
24 + 1 = 25 days

When the moving ellipse passes through the fixed point m (1,2), with the y-axis as the guide line and the eccentricity as 1 / 2, the trajectory equation of the left vertex and the maximum and minimum length of the major axis of the ellipse are obtained

Let P (x, y) be the left vertex, and let e = 0.5 know the left focus f (3 / 2x, y). Let | MF | / 1 = e be defined as 9 (X-2 / 3) ^ 2 + 4 (Y-2) ^ 2 = 1
M is the left vertex, the length of major axis is the largest, a ^ 2 / C-A = 1, C / a = 1 / 2, then a = 1, 2A = 2
M is the right vertex, the length of major axis is the smallest, a + A ^ 2 / C = 1, C / a = 1 / 2, then a = 1 / 3, 2A = 2 / 3

For triangles and parallelograms with equal base and height, if the area of a triangle is 25 square meters, the area of a parallelogram is 25 square meters______ ．

25 × 2 = 50 (square meters); answer: the area of parallelogram is 50 square meters