Inductor L = 1.59h, connected to u = 220sin314tv sinusoidal current, calculate inductive reactance XL and current I

Inductor L = 1.59h, connected to u = 220sin314tv sinusoidal current, calculate inductive reactance XL and current I

XL=wL=314*1.59=500Ω
I=U/XL=0.44sin314tA

In the circuit with known resistance and inductance in series, the power supply u = 220 V, resistance = 20 ohm, l = 0.1 h, f = 50 Hz, try to find the current I, resistance terminal voltage U (R) and inductance
Voltage U (L), and draw the phasor diagram
It seems that it also requires an angle or something

Inductive reactance, XL = ω L = 2 * π * f * l
= 2 * π * 50 * 0.1
=31.42 ohm (Ω)
The total impedance of this series circuit, z = √ (R ^ 2 + XL ^ 2)
= √（20 ^2 + 31.42 ^2）
=37.24 ohm (Ω)
Current, I = u / Z
= 220 / 37.24
=5.91 a
Terminal voltage of resistor, ur = I * r
= 5.91 * 20
=118.15 V
Terminal voltage of inductor, UL = I * XL
= 5.91 * 31.42
=185.62 V (V)
Vector angle = cotangent (XL / R)
=Cotangent (31.42 / 20)
= 57.52 °

3 out of 1.2, 1 out of 3, 3 out of 4

and than?

The image of a function of a degree passes through points (2,1) and (- 1, - 3) (1) to find the analytic expression of the function of a degree (2) to find the image of the function of a degree and its relation with x-axis and y-axis

Let the analytic expression of the function be y = KX + B
Substituting points (2,1) and (- 1, - 3) into the analytical expression, we get the following results:
1=2k+b
-3=-k+b
The solution of the equations is: k = 4 / 3
b=-5/3
So the analytical formula is y = 4x / 3-5 / 3
Let y = 0, then 0 = 4x / 3-5 / 3, x = 5 / 4
Let x = 0, then y = - 5 / 3
The intersection of image and coordinate axis is: (5 / 4,0) (0, - 5 / 3)

What is the prime factor of 36?

36=2*2*3*3
The prime factor of 36 is 2,3

If the quadratic power of (a + b) is known to be 13, (a-b) = 7, try to find ab

The second power of (a + b) = a ^ 2 + 2Ab + B ^ 2 = 13, and (a-b) = 7,
The second power of (a-b) = a ^ 2-2ab + B ^ 2 = 49
Subtraction of two formulas: 4AB = - 36
ab=-9

Prove by the definition of derivative: (a ^ x) '= a ^ x · LNA

Y = a ^ x, ⊿ y = a ^ (x + ⊿ x) - A ^ x = a ^ x (a ^ ⊿ x-1) ⊿ Y / ⊿ x = a ^ x (a ^ ⊿ x-1) / ⊿ x if you directly let ⊿ x → 0, you can't derive derivative function, you must set an auxiliary function β = a ^ ⊿ X-1, and calculate it by substitution

The process and result of (12 * 21 * 45 * 10.2) / (15 * 4 * 0.7 * 51) formula

12 divided by 4 is 3
21 divided by 0.7 equals 30
45 divided by 15 is 3
10.2 divided by 51 equals 0.2
3×30×3×0.2=54

-The reciprocal of five and two fifths

27/5

4 (3x-1) ^ 2 = 9 (3x + 1) ^ 2 allocation method 2x ^ 2 - 5x + 3 = 0
Solving equation 4 (3x-1) ^ 2 = 9 (3x + 1) ^ 2
Using the distribution method 2x ^ 2 - 5x + 3 = 0

2x^2 -5x+3=(X-1)(2x-3)
The original left and right radical at the same time
2(3X-1)=3(3X+1)
6X-2=9X+3
3X=5
X=5/3
What is the distribution method?