When the phase difference between them is 0 degree, 90 degree and 180 degree, the maximum value of their combined current I1 + I2 is calculated respectively Why 5 * √ 2 / 2?

When the phase difference between them is 0 degree, 90 degree and 180 degree, the maximum value of their combined current I1 + I2 is calculated respectively Why 5 * √ 2 / 2?

The phase difference is 0 degrees, and the maximum combined current is 5 + 5 = 10A,
The phase difference is 90 degrees, and the maximum synthesis current (radical 2) / 2x5 + (radical 2) / 2x5 = 5 (radical 2) = 7.07a
The phase difference is 180 degrees, and the maximum synthetic current is 5-5 = 0A
Sin (a + 90) + Sina < = 2xsin45 = 2x radical 2 / 2 = radical 2 = 1.414

The maximum value of two sinusoidal currents I1 and I2 is 5A. When their phase difference is 90 degrees, what is the maximum value of I1 + I2
A why is it 45 degrees?

Can you imagine a vector graph, a Y-axis and an x-axis, with a length of 5 and a hypotenuse as a composite vector, not 45?, Pythagorean theorem, the maximum value is equal to 5 * √ 2

Sine current I1 = 100sin (WT + 45), I2 = 60sin (WT-30). How to use phasor diagram to solve I = I1 + I2?

The length at 45 degrees to the x-axis is 100
The length of - 30 degrees from the x-axis is 60
It's just vector superposition

Given that point a (x + 3, Y-12) and point B (2x-1, 3Y + x) are symmetric about the X axis, the area of triangle OAB is ()

First of all, for X-axis symmetry, the abscissa is equal, and the ordinate is opposite to each other. We can get x = 4, y = 2. In this case, a (7, - 10) B (7,10)
The answer is 70

There are 56 students in the class. Boys are 25% less than girls

56 △ 1 + (1-25%), = 56 △ 1.75, = 32 (person); answer: there are 32 female students

Factorization: x ^ 2-6y ^ 2-12z ^ 2 + xy-xz + 17yz

Square of. X - square of 6y - square of 12z + XY XZ + 17yz
=x^2+x(y-z)-(6y^2-17yz+12z^2)
=x^2+x(y-z)-(2y-3z)(3y-4z)
=(x-2y+3z)(x+3y-4z)

There are 153 students in the third grade of a school. Two thirds of the boys are equal to three quarters of the girls

Male 153 △ 1 + 2 / 3 △ 3 / 4
=153÷（1+8/9）
=153÷17/9
=81
Female 153-81 = 72

Given that the x power of a is 1 / 2, and the Y power of B is 1 / 3, then the x power of 1 / 3 (the square of a) is divided by (the third power of B)
The value of Y power of is

-9 / 8, I took a picture. I don't know if you can receive it

In the sixth grade of a primary school, the number of girls was 80% of that of boys, and then two girls were transferred. At this time, the number of boys was 120% of that of girls. How many people were there in the whole grade?

A: there are 108 people in the whole class

Xiao Mahu solves the equation 3 / (2x-1) = 2 / (x + a) - 1. When the denominator is removed, the - 1 on the right side of the equation forgets to multiply by 6, so the solution obtained is x = 4, and a and B are obtained
Xiao Mahu solves the equation 3 / (2x-1) = 2 / (x + a) - 1. When the denominator is removed, the - 1 on the right side of the equation forgets to multiply by 6, so the solution obtained is x = 2, and a and the correct solution are obtained

Substituting x = 2 into 2 (2x-1) = 3 (x + a) - 1 leads to
6=6+3a-1
∴3a=1
After the denominator of the original equation is removed
2(2x-1)=3(x+a)-6
4x-2=3x+3a-6
x=3a-4
x=-3