In a sinusoidal AC circuit with resistive elements, the volt ampere relationship is wrong A. U = IR B, u = IR C, u = IR r the last option is that u and I are phasors. I think C is wrong. Phasor u = Z times phasor I

In a sinusoidal AC circuit with resistive elements, the volt ampere relationship is wrong A. U = IR B, u = IR C, u = IR r the last option is that u and I are phasors. I think C is wrong. Phasor u = Z times phasor I

A. U = I r, lowercase is instantaneous value, the value of R is the proportion of u and I, correct
B. U = I r, this is the expression of DC circuit, error
C. U '= I' R, AC circuit phasor type, resistance load, u 'and I' have the same phase, the value of R is the proportion of U 'and I', correct

1. When the sinusoidal voltage U = 10sin (314T + 30 °) V is applied to a 5W resistance element, the current passing through the element i = ()
A、 2 sin314t AB、 2 sin( 314t+30° ) A C、 2 sin( 314t－30° ) A D、2A
3. A triangle connected three-phase symmetrical load is connected to three-phase symmetrical power supply, and the phase relationship between line current and its corresponding phase current is ()
A. Line current leads to 30 ° front phase current
B. The line current lags the phase current by 30 degrees
C. The two are in the same phase
D. The two are opposite

1. When the sinusoidal voltage U = 10sin (314T + 30 °) V is applied to a 5W resistance element, the current passing through the element i = (b);
2 sin( 314t+30° ) A
2. The phase relationship between the line current and its corresponding phase current is (a);
Line current leads to 30 ° front phase current

(1) As shown in Figure 1, take the sides AB and AC of △ ABC as sides to make square ABDE and square acfg outward respectively, connect eg, try to judge the relationship between △ ABC and △ AEG area, and explain the reason. (2) garden path, winding path leads to secluded, as shown in Figure 2, the small path is paved with white square marble and black triangular marble. It is known that the sum of all squares in the middle is a square meter The sum of the area of all the triangles in the inner circle is b square meters

(1) The area of △ ABC is equal to that of △ AEG. Reason: if cm ⊥ AB is set at m through point C, GN ⊥ EA through point G, and EA extension line is set at n, then ∠ AMC = ∠ ang = 90 °, both ∵ Quad ABDE and Quad acfg are square, ∵ Bae = ∠ CAG = 90 °, ab = AE, AC = AG,