Given that X and y satisfy the square of X + 4Y = 2x + 4Y-2, find the square root of x-2y

Given that X and y satisfy the square of X + 4Y = 2x + 4Y-2, find the square root of x-2y

Square of X + square of 4Y = 2x + square of 4Y-2 x + square of 4y-2x-4y + 1 + 1 = square of 0 (x-1) + (square of 2y-1) = 0, X-1 = 0, 2y-1 = 0, x = 1, y = 1 / 2, x-2y = 1-1 = 0, square root of x-2y = 0

The function f (x) satisfies f (x) * f (x + 2) = 13, if f (1) = 2, then f (99) =

f（x）*f（x+2）=13
Then f (x + 2) * f (x + 4) = 13
be divided by
f(x+4)/f(x)=1
f(x+4)=f(x)
Then f (99) = f (95) = f (91) = f(3)
Let x = 1
f(1)f(3)=13
So f (99) = f (3) = 13 / 2

The coordinates of the intersection of the straight line y = - X and the parabola y = - x

(0,0) (1,-1)

Symmetry axis of quadratic function y = ax ^ 2 + BX + C image
Given two coordinates (0, - 1) (4, - 1), find the symmetry axis of quadratic function y = ax ^ 2 + BX + C

C = - 1
Because: - 1 = 16A + 4B + C
So: 16A + 4B = 0
That is: B = - 4A
And because the axis of symmetry: x = - B / 2A = - (- 4A) / 2A = 2

When x satisfies what conditions, the following expressions are meaningful? (1) √ 1-4x (2) x √ x + 1 (3) √ X-2

1. X is less than a quarter
2. X is greater than or equal to minus one and not equal to zero
3. X is greater than zero

It is known that the solution of the equation MX + 2 = 2 (M-X) about X satisfies / (absolute value) X-1 / (fractional line) 2 / (absolute value) - 1 = 0

|X-1/2|=1
X = 1 / 2 ± 1, x = 3 / 2 or - 1 / 2,
① When x = 3 / 2,
3/2m+2=2(m-3/2)
3/2m+2=2m-3
1/2m=5,
m=10,
② When x = - 1 / 2,
-1/2m+2=2(m+1/2)
-1/2m+2=2m+1
5/2m=1
m=2/5.

a(x²-4)=x(a²-4)(a≠0)

A (X & # 178; - 4) = x (A & # 178; - 4) (a ≠ 0) ax & # 178; - 4A XA & # 178; + 4x = 0ax (x - a) + 4 (x-a) = 0 (AX + 4) (x-a) = 0, x = a or ax = - 4, x = a or x = - 4 / 4, benefactor, I think you are a unique talent in the Wulin

(2x-1) (x + 2) - (X-2) & # 178; - (x + 2) & # 178; predigestion

（2x-1）（x+2）-（x-2）²-（x+2）²
=2x²+4x-x-2-(x²-4x+4)-(x²+4x+4)
=2x²+4x-x-2-x²+4x-4-x²-4x-4
=3x-10

The solution of one variable linear equation 0.5x + 1 = 0 is the image and function of one order function y = 0.5x + 1______ The abscissa of

The abscissa of the intersection of x-axis and image of ∵ 0.5x + 1 = 0, ∵ 0.5x = - 1, ∵ x = - 2, ∵ linear function y = 0.5x + 1 is: x = - 2, so the answer is: X-axis intersection

If the fourth-order matrix A is similar to B and the eigenvalues of matrix A are 1 / 2 1 / 3 1 / 4 1 / 5, then the determinant | b * - e | =?

The eigenvalues of a are 1 / 2,1 / 3,1 / 4,1 / 5,
Similarly, the eigenvalues of B are 1 / 2,1 / 3,1 / 4,1 / 5,
The eigenvalues of B ^ (- 1) are 2,3,4,5
B = 1 / 2.1/3.1/4.1/5 = 1 / 120,
The eigenvalues of | b * = | B | · B ^ (- 1) = 1 / 120 · B ^ (- 1) are: 1 / 60,1 / 40,1 / 30,1 / 24,
The eigenvalues of B * - E are - 59 / 60, - 39 / 40, - 29 / 30, - 23 / 24,
∴ |B*-E| = (-59/60)(-39/40)(-29/30)(-23/24) = 511589/576000.