As shown in the figure, point C is the midpoint of AB, ad = CE, CD = be

As shown in the figure, point C is the midpoint of AB, ad = CE, CD = be

In △ ACD and △ CBE, ad = CECD = beac = CB, (5 points) ≌ ACD ≌ CBE (SSS). (6 points)

There is a saying: in the linear motion of a single line, scalar distance and vector displacement are the same thing. Is displacement a vector?

Distance and displacement are definitely not the same thing
The distance is a scalar and the displacement is a vector

Find the center locus of a given circle X & # 178; + Y & # 178; - 6mx-2 (m-1) y + 10m & # 178; - 2m-24 = 0 (m ∈ R)

The roundness can be changed into the standard formula
(x-3m)^2+[y-(m-1)]^2=25
Then let the center of the circle be (x, y)
Then x = 3M
y=m-1
Then M = y + 1
That is, x = 3 (y + 1)
So the trajectory equation of the center is: x-3y-3 = 0

(E ~ x) (1 + e ~ x) ~ 5 for indefinite integral

Is that e ~ x an e ^ x? Is it an index? ∫ e ^ x (1 + e ^ x) ^ 5 DX = ∫ e ^ x (5e ^ x + 10e ^ 2x + 10e ^ 3x + 5E ^ 4x + e ^ 5x + 1) DX = ∫ e ^ x + (5 / 2) e ^ 2x + (10 / 3) e ^ 3x + (5 / 2) e ^ 4x + e ^ 5x + (1 / 6) e ^ 6x + C = (1 / 6) e ^ x (e ^ x + 2) (e ^ x +

English translation
a man's reach should exceed his grasp or what's a heaven for?

A person's attainable achievements should exceed his knowledge, otherwise, who is heaven for?
It means: people should pursue excellence and surpass themselves to enter heaven. Heaven is for these people

If it's an equation, it needs a process, and the arithmetic method is better
There was a batch of goods, half and a half tons of which were transported in the first time, half and a half tons of which were left in the second time, and half and a half tons of which were left in the third time. It was just finished. How many tons were there in this batch of goods?

There was a batch of goods, half and a half tons of which were transported in the first time, half and a half tons of which were left in the second time, and half and a half tons of which were left in the third time. It was just finished. How many tons were there in a batch of goods?
[analysis]:
The problem is solved by the method of "backward deduction"
First of all, I want to start with "half and half a ton of the remaining goods will be transported the third time, and it's just finished.",
Half a ton is exactly half of the goods left after the second shipment. It can be seen that half and half a ton of the goods left after the second shipment,
The remaining cargo is 0.5 × 2 = 1 (ton)
This one ton plus half a ton is half of the goods left after the first shipment,
Therefore, after the first shipment, the remaining cargo is (1 + 0.5) × 2 = 3 (tons)
Three tons plus half a ton is exactly half of the original total,
So the original goods are (3 + 0.5) × 2 = 7 (tons)
A: there were originally 7 tons of the goods

The formula of perimeter of parallelogram

Twice the sum of the adjacent sides

Finding the domain of the function y = log2 (x + 4)

Because 2 (x + 4) > 0, so x + 4 > 0, so x > - 4

all of the houses on my street decided to purchase new numbers for their address from the same store to post on their front doot.Assume that the addresses start with pecan st,2 pecan st,3 pecan st and do not skip any inteers.also ,assume that the houses visit the hardware storein increasing order.if billiy bobb's hardwad only has 100 of each digit available,which house will be the first not to be able to purchase all of its necessart digits?
The wealth value of the first answer is 50 points

Because each number is only 100, so the fastest one to use up must be number 1. So just calculate where the 100th number 1 is used
99 use "1" 20 times
100 ~ 159 use "1" 76 times
There are still four "1's" left, which are only used to make door numbers 160, 161 and 162
So the first number that can't be completed is 163

It is known that the three vertices of ABC are a (4,0) B (6,7) C (0,3)
Solving the linear equation of the height on the BC edge
Finding ABC area of triangle

Kbc=(7-3)/6-0)=2/3
The equation (y-0) = - 3 / 2 (x-4)
y=-3x/2+2
ABC area = 6 * 7-7 * (6-4) / 2-4 * 3 / 2-6 * (7-3) / 2
=42-7-6-12
=27