The standard equation of hyperbolic equation with the same focus as the ellipse x2 / 10 + Y2 / 4 = 1 and passing through the point (5, - 2)

The standard equation of hyperbolic equation with the same focus as the ellipse x2 / 10 + Y2 / 4 = 1 and passing through the point (5, - 2)


The focus coordinate of the ellipse is F1 (- radical 6,0) F2 (radical 6,0)
That is, C = root 6
So let the hyperbolic equation be x ^ 2 / A ^ 2-y ^ 2 / b ^ 2 = 1
c^2=a^2+b^2=6
25/a^2-4/b^2=1
The solution is a ^ 2 = 5, B ^ 2 = 1
That is, the equation is x ^ 2 / 5-y ^ 2 = 1



There is a two digit number. The difference between it and 1 is a prime number. The quotient obtained by dividing it by 2 is also a prime number. The remainder obtained by dividing it by 9 is 5. What is the number?


Try it first
1*9+5=14
The checking calculation is just right
So it's 14



The solution set of inequality logx-4 (2x-8) > logx-4 (x-3) is ()
A. {x | x > 4} B. {x | x > 5} C. {x | 4 < x < 5} D. {x | x > 4 and X ≠ 5}


Logx-4 (2x-8) > logx-4 (x-3) ⇔ x − 4 > 12x − 8 > x − 3 > 0 or 0 < x − 4 < 10 < 2x − 8 < x − 3, the solution is x > 5 or 4 < x < 5, so the solution set of inequality is {x | x > 4 and X ≠ 5}



Example 1: when x > 0, f (x) = x & # 178; + 2x-1, why do we have to set x > 0 - x < 0
We can't set X or > 0 - x < 0


Because this function is not monotone when x > 0, it should be set separately



Proof: there is only one prime P, so that P + 10 and P + 14 are prime numbers


Certification:
If P = 3K + 1, then p + 14 = 3K + 15 = 3 (K + 5) is a composite number
If P = 3K + 2, then p + 10 = 3K + 12 = 4 (K + 3) is a composite number
Therefore, only when p = 3K can p + 10 and P + 14 be prime numbers
But there is only one prime number P = 3K
So 3 is the only prime P that makes p + 10 and P + 14 prime



Find the edge density function, f (x, y) = {6xy ^ 2, 0
0


If we find f (x), we will find the integral for y. if we find f (y), we will find X. if f (x, y) = f (x) f (y), we can also find X and Y independent
The basic solution is: because it is uniformly distributed, its density function is a constant. You can calculate the area of that area,
It's 6, so the density function in that area is 6, and the rest are 0, and then you can integrate them separately



Function y = asinx + B (a)


Since SiNx takes [- 1,1]
a



If a times two-thirds = B times three-quarters, then a () B A is greater than B and less than C equals


A is greater than
Any questions are welcome



The bottom of a trapezoid is 18 cm. If the bottom is shortened by 8 cm, it becomes a parallelogram,
Area reduces 28 square centimeter, the height of original trapezoid is how many centimeter?


Because the bottom of the trapezoid is shortened by 8 cm, it becomes a parallelogram. Then the area of the triangle with the bottom of 8 cm should be reduced by 28 square cm, and the height h = 28x2 divided by 8 = 7 cm



What is the basis for making an angle equal to a known angle in ruler and gauge drawing


It is the basis to make an angle equal to the known angle in ruler and gauge drawing
"Two triangles with equal sides are congruent, and the corresponding angles of congruent triangles are equal."