Let z = 3 ^ XY, then &; Z / &; X =?

Let z = 3 ^ XY, then &; Z / &; X =?

According to: (a ^ x) '= xlna
∂z/∂x=∂(3^xy)/∂x=xyln3*y=xy^2ln3

Given the function z = f (x ^ 2-y ^ 2, XY), find &; Z / &; X, &; Z / &; y, please help

∂z/∂x＝∂z/∂(x^2-y^2)*∂(x^2-y^2)/∂x+∂z/∂(xy)*∂(xy)/∂x=∂z/∂(x^2-y^2)*2x+∂z/∂(xy)*y∂z/∂y=∂z/∂(x...

Let z = XLN (XY) find &; 3Z / &; X &; y and &; 3Z / &; X &; y and &; y;

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High number problem: x ^ 2 + y ^ 2 + Z ^ 2-4x = 0, z = f (x, y), find (&; &; Z) / (&; X &;)?
High number problem solving! X ^ 2 + y ^ 2 + Z ^ 2-4x = 0, z = f (x, y), find (&; & # 178; Z) / (&; X & # 178;)?

For rational numbers a and B, define a ⊙ B = 3A + 2B, then [(x + y) ⊙ (X-Y)] ⊙ 3x is reduced to ()
A. 0B. 5xC. 21x+3yD. 9x+6y

∵ a ⊙ B = 3A + 2B, ∵ [(x + y) ⊙ (X-Y)] ⊙ 3x = [3 (x + y) + 2 (X-Y)] ⊙ 3x = (3x + 3Y + 2x-2y) ⊙ 3x = (5x + y) ⊙ 3x = 3 (5x + y) + 2 × 3x = 15x + 3Y + 6x = 21x + 3Y

It is known that the left focus of the ellipse x2 / 2 + y2 = 1 is f, and O is the origin,
Let the intersection ellipse of the straight line passing through the point f not perpendicular to the coordinate axis and the vertical bisector of the two line segments a and B intersect with the X axis at g, and then calculate the value range of the abscissa of point G

The ellipse satisfies a ^ 2 = 2, B ^ 2 = 1, C ^ 2 = a ^ 2-B ^ 2 = 1, so the coordinate of point F is (1,0). Let the equation of line AB be y = K (x + 1) and the ellipse equation. By eliminating y, the abscissa of two points of AB can be obtained. Take the average value, that is, the abscissa of midpoint AB is x1x1 = - 2K ^ 2 / (2k ^ 2 + 1) and substituting y = K (x + 1), the ordinate of midpoint AB is y1y1y1 = K

In the triangle ABC, given BC = 4, AC = 5, ab = 6, find the length ad of the center line on the side of BC

cosC=16+25-36/2*4*5=1/8
cosC=4+25-x~2/2*2*5=1/8
The solution is x = 53 under the root sign

If x is a pure imaginary number, y is a real number, and 2x-1 + I = y - (3-y) I, then x + y equals ()
A. 1+52iB. -1+52iC. 1-52iD. -1-52i

∵ x is a pure imaginary number, let x = AI (a ≠ 0), and y be a real number, and 2x-1 + I = y - (3-y) I, ∵ (2a + 1) I-1 = y - (3-y) I, ∵ y = − 12a + 1 = y − 3, the solution is a = - 52, y = - 1, ∵ x + y = - 52i-1, so choose D

Given function F X = 3 / 2Sin (2x + π / 4)
Finding the minimum positive period and monotone decreasing interval of function F X

Minimum positive period T = 2 π / 2 = π
The monotone decreasing interval is 2K π + π / 2

In RT △ ABC, ∠ C = 90 ° and AC = 5cm, ab = 13cm, then BC=______ cm．

As shown in the figure: ∵ RT △ ABC, ∠ C = 90 °, AC = 5cm, ab = 13cm, ∵ BC = AB2 − ac2 = 132 − 52 = 12cm