Comparison size: log (1 / 2) ^ 5, log2 ^ 3, 1, 3 ^ (- 0.2)

Comparison size: log (1 / 2) ^ 5, log2 ^ 3, 1, 3 ^ (- 0.2)

log2^3>1>3^(-0.2)>log(1/2)^5
Because log2 ^ 3 > 1, 1 > 3 ^ (- 0.2) > 0, 0 > log (1 / 2) ^ 5, well, that's it~

Log2 (1 / 2) and log2 ((a ^ 2 + A + 1)) compare sizes
Log2 (1 / 2) means the logarithm of 1 / 2 with the base of two

log2((a^2+a+1))=log2((a+1/2)^2+3/4)
Because ((a + 1 / 2) ^ 2 + 3 / 4) > 3 / 4
So log2 (1 / 2)

It is known that the coordinates of the three vertices of the triangle ABC are a (- 2,3), B (1,2), C (5,4), and the coordinates of the vectors Ba and BC and ∠ B are obtained

BA=OA-OB=(-2,3)-(1,2)=(-3,1),BC=OC-OB=(5,4)-(1,2)=(4,2)
BA · BC = (- 3,1) · (4,2) = - 10 = | BA | * | BC | * CoSb, so: CoSb = BA · BC / (| BA | * | BC |)
=-10 / (sqrt (10) * 2 * sqrt (5)) = - sqrt (2) / 2, so B = 3 π / 4

The bottom of a cuboid is a square with a circumference of 16 cm and a height of 3 cm. What is the volume of the cuboid?

16 △ 4 = 4 (CM), 4 × 4 × 3 = 48 (CC). A: the volume of this cuboid is 48 CC

Given Tana / 2 = - 1 / 2, find the value of COS (a - π / 6)

According to the universal formula
sina=(2tana/2)/(1+tan²a/2)
=[2×(-1/2)]/[1+(-1/2)²]
=-1/(5/4)
=-4/5
cosa=(1-tan²a/2)/(1+tan²a/2)
=[1-(-1/2)²]/[1+(-1/2)²]
=(3/4)/(5/4)
=3/5
cos(a-π/6)=cosacosπ/6+sinasinπ/6
=3/5×(√3)/2-4/5×1/2
=(3√3-4)/10

When m takes what value, there are two equal roots of the equation x ^ 2-2 (2m + 1) x + 2 (2m + 1) x + 3M ^ 2 + 5m + 7 = 0
Resolve "(2000 (1 + x) - 1000) (1 + x) = 1060.8he 9000 (1 + 0.5) ^ 2 = 9000 + 2500

The equation x ^ 2-2 (2m + 1) x + 2 (2m + 1) x + 3M ^ 2 + 5m + 7 = 0 has two equal roots? Find the root of the equation
-2(2m+1)X+2(2m+1)X=0
3m^2+5m+7=0
x1=x2=0

The odd function f (x) satisfies: ① f (x) increases monotonically in (0, + ∞); ② f (1) = 0; then the solution set of inequality (x-1) f (x) > 0 is as follows:______ ．

When x ＞ 1, f (x) increases monotonically in (0, + ∞), and f (1) = 0, then f (x) ＞ 0. When 0 ＜ x ＜ 1, f (x) ＜ 0, and the function f (x) is odd, then f (- 1) = 0 and f (x) increases monotonically in (- ∞, 0), then when - 1 ＜ x ＜ 0, f (x) ＞ 0, when x ＜ - 1, f (x) ＜ 0, so the answer is: (- ∞, - 1) ∪ (0, 1) ∪ (1) ，+∞）．

Answer No.2 correctly, x, 10x - (8-x) * 6 = 64, x = 7; how to solve the equation

10x-(8-x)*6=64
10x-48+6x=64
10x+6x=64+48
16x=112
x=112÷16
x=7

It is known that the center of the ellipse is at the origin, the focus is on the ㄨ axis, the length of the major axis is twice the length of the minor axis and passes through the point m (2,1)!

From the meaning of the title, 2A = 2 * 2B, that is, a = 2B
Let the equation be x ^ 2 / (4B ^ 2) + y ^ 2 / b ^ 2 = 1
(2,1) substitute 4 / (4B ^ 2) + 1 / b ^ 2 = 1
B ^ 2 = 2
So the equation is x ^ 2 / 8 + y ^ 2 / 2 = 1

How many centimeters is 0.314 meters,

0.00314