Limx tends to 0 √ x-3x + 2 to find the limit

Limx tends to 0 √ x-3x + 2 to find the limit

lim (x->0)√(x-1)(x-2)
=lim(x->0)=2

Why is the limit of [(2x-3) ^ 20 * (3x + 2) ^ 30] / (2x + 1) ^ 50 (2 / 3) ^ 30 when x tends to infinity?

Lim [(2x-3) ^ 20 * (3x + 2) ^ 30] / (2x + 1) ^ 50] = LIM (2-3 / x) ^ 20 * LIM (3 + 2 / x) ^ 30 / LIM (2 + 1 / x) ^ 50 = [LIM (2-3 / x)] ^ 20 * [LIM (3 + 2 / x)] ^ 30 / [LIM (2 + 1 / x)] ^ 50 = 2 ^ 20 * 3 ^ 30 / 2 ^ 50 = 3 ^ 30 / 2 ^ 30 = (2 / 3) ^ 30

A and B both drive from city a to city B for 300 km. Knowing that car a starts 1:00 later than car B, but arrives 1:00 earlier, how far is it from city B for car a to catch up with car B?

150KM

Help to solve this equation: (29 + 2x) (22 + 2x) = 29x22 + 0.25x29x22
The lowercase (x) is the unknown and the uppercase (x) is the multiplier
The process also needs
The accuracy was 0.1cm
I forgot to say it.

（29+2x）（22+2x）=29X22+0.25X29X22
4x²+22*29+2x*（22+29）=29*22*（1+0.25）
4x²-22*29*0.25+2x*（22+29）=0
x1=（-51+√3739）/4
x2=（-51-√3739）/4

The distance between city a and city B is 450 km. Two cars leave the two cities at the same time and meet in three hours. It is known that the speed ratio of car a and car B is 3:2. How many kilometers does the express train travel per hour

Car a 90
Car B 60

There is a two decimal place. The difference between the decimal point and the original number is 651.78. What is the original number?
Such as the title

Move 1 bit to the right, expand the value by 10 times, subtract the original value by 9 times, the original number should be the difference divided by 9
651.78/9=72.42

A bus and a train depart from a and B at the same time. The speed of the bus is 125% of that of the truck
one hundred and eleven
After meeting, the truck continues to drive for 15 minutes to reach the destination. How many minutes will the two vehicles meet after they leave at the same time?

(1 / 4) * V = 1.25V * t t is the required time. 0.2 hours (12 minutes)

For any real number x, there exists y such that x + Y > 0. What is the negation of this proposition
For any real number x, there exists y such that x + Y > 0. What is the negation of this proposition
I don't know what cause and effect is

The original proposition is: if x + Y > 0 holds for any real number x, then y exists
The negation is: if x + y ≤ 0 holds for any real number x, then y does not exist

The distance between station a and station B is 1280 km. After adopting the "harmony" EMU to increase the speed, the train speed is 3.2 times of the original speed, and the time from station a to station B is shortened by 11 hours, so the speed of the train after increasing the speed can be calculated

Suppose the speed of the train before the speed increase is x km / h, then the speed after the speed increase is 3.2X km / h. according to the meaning of the question, we can get: 1280 x-12803.2x = 11. Solving this equation, we can get: x = 80. After the test, x = 80 is the root of the equation listed. 80 × 3.2 = 256 (km / h). Answer: the speed of the train after the speed increase is 256 km / h

The average of the three numbers is 6. The ratio of the three numbers is 1 / 2:2 / 3:5 / 6. The three numbers are

Let these three numbers be 1 / 2x, 2 / 3x and 5 / 6x
(1/2x+2/3x+5/6x)/3=6
2x=18
x=9
1/2*9=9/2
2/3*9=6
5/6*9=15/2
These three numbers are 9 / 2, 6, 15 / 2