Material: try to discuss the solution of the equation AX = B When a ≠ 0, the equation has a unique solution x = 7 / A; When a = b = 0, the equation has innumerable solutions; When a = 0, B ≠ 0, the equation has no solution Given that the equation a (2x - 1) = 3x - 2 about X has no solution, find the value of A

Material: try to discuss the solution of the equation AX = B When a ≠ 0, the equation has a unique solution x = 7 / A; When a = b = 0, the equation has innumerable solutions; When a = 0, B ≠ 0, the equation has no solution Given that the equation a (2x - 1) = 3x - 2 about X has no solution, find the value of A

a（2x-1）=3x-2
2ax-a=3x-2
(2a-3)x=a-2
x=(a-2)/(2a-3)
So when A-2 ≠ 0 and 2a-3 = 0, the original equation has no solution,
That is, when a = 1.5, the equation a (2x-1) = 3x-2 has no solution

Materials: try to discuss the solution of the equation AX = B: when a ≠ 0, the equation has a unique solution x = B / A; when a = b = 0, the equation has countless solutions; when a = 0, B ≠ 0
Given that the equation a (2x - 1) = 3x - 2 about X has no solution, find the value of A

The known equations are sorted out
(2a-3)x=a-2
So when 2a-3 = 0, that is, a = 3 / 2, the original equation has no solution

The domain of the function y = LG 3x-1 over 3-x is____

y=lg[(3x-1)/(3-x)]
10^y=(3x-1)/(3-x)
10^y>0
(3x-9)/(3-x)+8/(3-x)>0
8/(3-x)>3
3-x > 0

I only have you in my eyes

I only have eyes for you

What is 1 ppm equivalent to parts per million?

One ppm is one part per million
Ppm is a percentage of weight, which means "parts per million..." For example, 1ppm is one part per million, 150ppm is 150 parts per million and so on

Given the function f (x) = log2x, if the sequence 3, f (x1), f (x2) (I) find the general formula of the sequence {f (xn)} (1 ≤ n ≤ m, m, n ∈ n *); (II) find the first n terms and Sn of the sequence {xn} (1 ≤ n ≤ m, m, n ∈ n *)

(I) sequence 3, f (x1), f (x2) If the tolerance is D, then 3 + (M + 1) d = 3M + 6, then d = 3, then f (x1) = 3 + 3 = 6, then f (xn) = 6 + (n-1) · 3 = 3N + 3, (II) since f (xn) = log2xn = 3N + 3, then xn = 23n + 3, then Sn =

Say some interesting abbreviations in English

lyk.like dat...that izz.is ppl...people rt.right LOL...laugh out loud ur.you 're/your cuz.cause b' cuz.because gewd.good dnt.didn 't/don't cnt.can 't fone.phone i luv u.I love you dis.this

It is proved that the square difference of two consecutive odd numbers is a multiple of 8

Let two continuous odd numbers be 2n-1,2n + 1
Where n is an integer
Two continuous odd square differences:
(2n+1)²-(2n-1)²
=(2n+1+2n-1)(2n+1-2n+1)
=4n*2
=8N is a multiple of 8

Please help to prove that binary function does not necessarily have partial derivatives at continuous points,

Take a counter example
For example, z = √ (x ^ 2 + y ^ 2), the definition field is x, y is r, and the function is continuous
z'x=x/√(x^2+y^2)
z'y=y/√(x^2+y^2)
When x = 0, y = 0, the partial derivative does not exist
When y approaches 0 along y = KX, limz'x = 1 / √ (1 + K ^ 2), it will vary with K, so there is no partial derivative at point (0,0)

How to calculate 52.89 - (13.54 + 6.89) with a simple method

52.89-(13.54+6.89)
=52.89-6.89-13.54
=46-13.54
=42.46