Special solution of differential equation y '+ 2XY = x, y (0) = - 2

Special solution of differential equation y '+ 2XY = x, y (0) = - 2

In this case, we will set the y = C0 (x) and (x) let the (x) e ^ (- x ^ 2) C0 (x) and (x ^ 2) our (x) e ^ (- x ^ 2) C0 (x) our (x) and (x) we will be (x) e ^ (- x ^ 2) our (x) e ^ (- x ^ 2) C0 (x) and (2XY = 2xydy / Y / y = -2xdx-2xdx) in this case, we will set the y = C0 (x) and (x (x) let (x (x) and (x) let (x ^ 2 (x ^ 2) as (x ^ 2) as (x ^ 2) the (x ^ 2 (x ^ 2) will be the (x ^ 2) we will be the (x ^ 2 (x ^ 2) in this (x ^ 2) will be the (x ^ x ^ 2) in this is the case of this is the case that we will be the case of; D (e ^ x ^ 2

1×3＋1=2²,2×4+1=3²,3×5＋1=4²,4×6+1=5… (1) Please use the formula containing n to find the rule:_________

The rule is: n × (n + 2) + 1 = (n + 1) ^ 2
Note: (n + 1) ^ 2 represents the square of the whole (n + 1)

Fill in +, -, ×, △ or brackets between the numbers to make the formula true
(1) 4 4 4 4=2 (2) 4 4 4 4=2 (3) 4 4 4 4=2
(4) 2 2 2 2 2 =2 (5) 3 3 3 3 3=10

(1) (4 × 4)÷ (4 ＋ 4）=2
(2) 4 ÷ (4 ＋ 4) × 4=2
(3) 4 ÷ 4 ＋ 4 ÷ 4=2
(4) 2 － 2 － 2 + 2 ＋ 2 =2
(5) (3 × 3 × 3 ＋ 3) ÷ 3=10

In the space rectangular coordinate system oxyz, the normal vector n of the plane OAB = (2, - 2,1), and the known point P (- 1,3,2), then the distance from point P to the plane is?
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The plane passes through the origin, so the plane equation must be in the form of AX + by + CZ = 0, and we know the normal vector of the plane
A = 2, B = - 2, C = 1, because for any point (x, y, z) on the plane, the inner product of the normal vector and the point is exactly:
(x, y, z) n = 2x - 2Y + Z = 0, corresponding to the equation
Then, we use the formula of distance from point to plane (sqrt is the root sign and ^ 2 is the square)
d = | Ax0 + By0 + Cz0 | / sqrt (A^2 + B^2 + C^2)
= | -2 - 6 + 2 | / sqrt (4 + 4 +1) = 2.
Answer: 2

The asymptote equation is the standard equation that y is equal to plus or minus 3 / 4x and the hyperbola is solved through the point (2.1)

Y equals plus or minus 3 / 4x, i.e
b/a=3/4
Therefore, the standard equation of hyperbola can be set as follows:
x^2/16k^2-y^2/9k^2=1
Passing point (2.1)
Then K ^ 2 = 5 / 36
The standard equation of hyperbola is as follows:
9x^2/20-4y^2/5=1

If the product of two numbers is negative, what is the relationship between the symbols of the two numbers?

However, when you learn the expansion of the number system, there will be an I * I = - 1, I is an imaginary number, it is not a different sign

Compare the third power of log2, the 30th power of log20 and the 0.3rd power of log0.2

Change the base first, and change all to logarithm with 10 as the base
The third power of log2 = Lg3 / LG2
The 30th power of log20 = LG30 / LG20 = (Lg3 + LG10) / (LG2 + LG10) = (Lg3 + 1) / (LG2 + 1)
The 0.3 power of log0.2 = lg0.3 / lg0.2 = (lg3-lg10) / (lg2-lg10) = (lg3-1) / (lg2-1)
Lg3 / LG2 max (lg3-1) / (lg2-1) min
Here you use the most basic fraction to prove it on the draft paper
Just notice that lg3-1 and lg2-1 are both negative numbers

It is known that a and B are two unequal real roots of the quadratic equation x + (2m + 3) x + m with respect to X. if 1 / A + 1 / b = - 1, then the value of M is

Two unequal real roots of square of X + (2m + 3) square of X + M = 0
a+B=-(2m+3),aB=m^2
1/a+1/B
=(a+B)/aB
=-(2m+3)/m^2
=-1
m^2=2m+3
m^2-2m-3=0
(m-3)(m+1)=0
m1=3,m2=-1

Does division change multiplication sign with brackets
In parentheses
There are no brackets. If I want to add them, can I change the sign

20÷（4÷2）=20÷4×2=10；
20÷4×2=20÷（4÷2）=10

What word can be formed by Ma, another pronunciation of Mo
Don't use the word mopping

To move by pressing lightly with one's hand