How much is a liter of water?

How much is a liter of water?

One liter of water is equal to one kilogram of water, equal to two kilograms of water

Here is a mathematical problem solving, to complete the process. The above X2 is the square of X, Y2 is the square of Y. thank you!
The equation of a circle is x2 + y2 = 9, and a point passes through M (6,0). A is a moving point on circle B, and C is the midpoint of a and m?

Point A: (a, b)
C：（a/2+3,b/2)
a^2+b^2=9
(2Xc-6)^2+(2Yc)^2=9
The equation of C: (2x-6) ^ 2 + (2Y) ^ 2 = 9
4x^2-24x+4y^2+27=0

X2 is the square of X and Y2 is the square of Y
The equation of one circle is x2 + y2 = 1, the equation of the other circle is (x-3) 2 + (y-4) 2 = 16, and the equation of the common tangent passing through the intersection is?

The radius of the first circle is 1, and the radius of the second circle is 4,
The distance between the center of the circle C1 (0,0) C2 (3,4) is
d=√(3-0)^2+(4-0)^2=5,
So if you circumscribe two circles, you have three common tangents,
One of them is that the inner common tangent passes through the tangent point of two circles, and the two circles are directly subtracted to get the equation
3x+4y-5=0
The other two tangent lines must have an intersection point, which can make the intersection point form a right triangle similar to the center of two circles and the tangent point of two circles. By using the similarity, the coordinates of the intersection point (- 1, - 4 / 3) can be obtained, and the tangent slope is K,
From the angle formula
k=(4/3-3/4)/(1+4/3*3/4)=7/8
So one of them is y + 4 / 3 = 7 / 8 (x + 1)
That is 21x-24y-11 = 0
The other slope does not exist, so the equation is x = - 1
To sum up, there are three tangent equations
3x+4y-5=0 21x-24y-11=0 x=-1

The circumference of a semicircle paper is 10.28 cm. What is its area?

Circumference of semicircle
= half of circumference + diameter
＝πr＋2r
＝3.14r＋2r
＝5.14r
The radius is:
10.28 ÷ (3.14 + 2) = 2 (CM)
The area is:
3.14 × 2 × 2 △ 2 = 6.28 (square centimeter)

Simple calculation of 11 * 9 of 18-11 * 6 of 18 2.25 * 4.8 + 77.5 * 0.48

11 * 9 of 18-11 * 6 of 18
=11/18*(9-6)
=11*3/18
=11/6
2.25*4.8+77.5*0.48
=4.8*(2.25+7.75)
=48

In the triangle ABC, ad is perpendicular to D, be is perpendicular to AC and E, ad and be intersect at F. if BF equals AC, then the degree of angle ABC is?

∵ AD⊥BC,BE⊥AC ,
{ACD =} AFE (both are the residual angles of})} BFD =} AFE (opposite vertex angle)
← ACD = ∠ BFD (equivalent substitution)
And ∵ BF = AC
∴△BDF≌△ADC
∴BD＝AD
Therefore, ABC = 45 degree

If A1 / B1 = A2 / B2 = =an\bn(a1,a2,…… an,b2,…… B N are all positive integers), proving: √ A1B1 + √ a2b2 + √anbn
=√(a1+a2+a3+a4+…… +an)(b1+b2+b3+…… +bn)

The area of a triangle is equal to half of that of a parallelogram (√ / ×)

The condition of your question is not stated. If the only question is this sentence, it is wrong
The conclusion that the area of a triangle is equal to half of that of a parallelogram is conditional
In the case of the same base and height, the area of a triangle is equal to half of that of a parallelogram

If f (x) satisfies f (x ^ n) = lgx, then the value of F (2) is equal to

If f (x ^ n) = lgx, then f (2) =?
Solution 1: let x ^ n = 2
Then lgx ^ n = LG2
Then NLGX = LG2
Then lgx = (1 / N) LG2
So f (2) = (1 / N) LG2
Method 2
f(x^n)=lgx
Let t = x ^ n
x=t^1/n
f(t)=lg(t^1/n)
=1/nlgt
So f (x) = 1 / NLGX
f(2)=1/nlg2

If a bamboo pole is less than 6 meters long, measure it from one end to 3 meters and make a mark a, then measure it from one end to 3 meters and make a mark B. at this time, the distance between AB is 20% of the total length, then the length of the bamboo pole is______ Rice

(3 + 3) / (1 + 20%) = 6 / 120%, = 5 (m); answer: the length of bamboo pole is 5 m