Given that the product of five rational numbers is negative, then the number of positive factors in these five rational numbers is?

Given that the product of five rational numbers is negative, then the number of positive factors in these five rational numbers is?

2 or 4
Because the number of negative factors must be odd

30×6x+20×4x-6x×4x=¼×30×20

30×6x+20×4x-6x×4x=¼×30×20
180X+80X-24X²=150
24X²-260X+150=0
The solution is x1 ≈ 0.61, X2 ≈ 10.22

3x-24=6（x-5）

3x-24=6（x-5）
3x-24=6x-30
3x-6x=-30+24
-3x =-6
x =2
X = 2 is the solution of the original equation
(this is the standard format of the senior high school entrance examination. Don't blame me if it's wrong) (also, solving equations in primary school should not involve negative numbers, right?) (the answer is really 2)

If the roots of the equation x & # 178; - 2x = 2 are a and B respectively, then a + B =? A × B =? A × B =? A + B =? A × B =? A + B =? A + B =? A + B =? A × B =? A + B =? A × B =? A + B =? A × B = a?

x^2-2x-2=0
a+b=2
a*b=-2

Using C language to write a simple calculator that can carry out mixed operation of addition, subtraction, multiplication and division
requirement:
1. Can carry out + - * / four operations
2. Mixed operation can be performed, such as 4 + 5 * 6 = 34
As long as you can multiply, divide, add and subtract first, and complete the program, don't give only one paragraph, but also run

/* Note:Your choice is C IDE */#include "stdio.h"#include "stdlib.h"#include "ctype.h"int n=0;char record[20];float product();float change();float muli(){\x09float summ;\x09summ=product();\x09while(re...

Mathematical problems of quadratic equation of one variable
Square is replaced by @
1. It is better to solve the equation x @ + 2x-323 = 0
2. Given that K is nonnegative, the equation is solved x@- (K + 1) + k = 0 has two real roots, and the two real roots are obtained
3. If the equation about X x@-mx+2 And x@- If (M + 1) x + m has the same real root, then the value of M is
four x@-2ax+a@-b@ = 0 (solve the equation,
5. What is the value of K, the system of equations x-y-k = 0 x@-8y = 0? 2, there is a real solution? And the solution of the equations is obtained
6. A.B.C is △ ABC trilateral, if two equations x @ + 2aX + B @ = 0 and X @ + 2aX about X+（ c@-b@ ）Let's judge the shape of △ ABC

If you don't want to replace the formula, you can decompose the factor into 19-172k, which is not negative, so the root seeking formula flies to 0, and the factorization is 1 K3. If you substitute 2 equations and 2 roots into 1 m, what do you do? 4. If you decompose the factor, you - (a-b) - (a + b) divide it into 5, and the simultaneous root seeking formula is 0, 6

Mathematical binomial coefficient
4. If the sum of the coefficients in the expansion of is 1024, then the terms with integer power of X in the expansion are common
（ ）
A. 2 items B.3 items C.5 items d.6 items

According to the sum of the coefficients is 1024, let x = 1, find out the value of n as 5, let the coefficients A0, A1, A2, A3, A4, A5, in the general formula am, take the value of 0,1,2,3,4,5, list the general expression and sort out the value of M, and see that several terms are the power of X and are integers

It is known that a + B = 3, ab = 1 / 2
Find 1. The second power of a + the second power of B

a²+b²
=（a+b）²-2ab
=3 & # 178; - 2 × 1 / 2
=9-1
=8

When using image to solve the quadratic equation of one variable x2 + x-3 = 0, we adopt a method: draw a parabola y = x2 and a straight line y = - x + 3 in the plane rectangular coordinate system, and the abscissa of the intersection of two images is the solution of the equation. (1) fill in the blanks: using image to solve the quadratic equation of one variable x2 + x-3 = 0 can also be solved in this way: draw a parabola y in the plane rectangular coordinate system=______ (2) given the image of the function y = - 6x (as shown in the figure), the approximate solution of the equation 6x-x + 3 = 0 can be obtained by using the image. (results two significant numbers are reserved.)

(1) The approximate solution of equation 6x-x + 3 = 0 is: X1 = - 1.4, X2 = 4.4

x: 4 / 3 = 6 / 5 [solve equation, 9.6x = 4 [solve equation,

x：4/3=6/5
x=6/5*4/3=8/5
9.6x=4
x=4/9.6=1/2.4=10/24=5/12
If you ask questions from your mobile phone, just click "satisfied" in the upper right corner of the client