Find the equation of the circle which passes through the point m (3, - 1) and the circle C: x2 + Y2 + 2x-6y + 5 = 0 and is tangent to the point n (1,2). Why can't we use the equation of the circle system? Isn't there an intersection point between the tangent and the circle?

Find the equation of the circle which passes through the point m (3, - 1) and the circle C: x2 + Y2 + 2x-6y + 5 = 0 and is tangent to the point n (1,2). Why can't we use the equation of the circle system? Isn't there an intersection point between the tangent and the circle?

The major axis is three times of the minor axis, and the ellipse passes through the point P (6,0) to find the standard equation of the ellipse

It is known that: a = 3b, if the intersection is on the X axis, the equation is: x ^ 2 / A ^ 2 + y ^ 2 / b ^ 2 = 1, x ^ 2 / (9b ^ 2) + y ^ 2 / b ^ 2 = 1, the ellipse passes through P (6,0), 36 / (9b ^ 2) + 0 = 1, B = 2, a = 6, so the equation of ellipse is: x ^ 2 / 36 + y ^ 2 / 4 = 1, if the intersection is on the Y axis, the equation is: y ^ 2 / A ^ 2 + x ^ 2 / b ^ 2 = 1, y ^ 2 / (9b ^ 2) + x ^

The length of the major axis of the ellipse is three times that of the minor axis, and the standard equation is solved by P (3,0)

Classification
a=3b
(1) The focus is on the x-axis,
If a = 3, then B = 1,
Equation x & # 178 / 9 + Y & # 178; = 1
(2) The focus is on the y-axis,
B = 3, then a = 9
Equation y & # 178 / 81 + X & # 178 / 9 = 1