1. If the solution set of inequality 3 / 1 (x-m) > 2x-m is x < 2, then M=_____ 2. When x takes what value, the value of algebraic formula 2-2x is not less than the value of 3 [X-2 (x-1)]

1. If the solution set of inequality 3 / 1 (x-m) > 2x-m is x < 2, then M=_____ 2. When x takes what value, the value of algebraic formula 2-2x is not less than the value of 3 [X-2 (x-1)]

1,1 / 3 * (x-m) > 2x-m, remove bracket, get: X / 3-m / 3 > 2x-m, move item, get: X / 3-2x > m / 3-2m, merge similar items, get: - 5x / 3 > - 5m / 3, divide both sides by - 5 / 3, get: (note sign change) x = 3 [2-2x + 2], 2-2x > = 3 (4-2x), remove bracket, get: 2-2x > = 12-6x, move item, get: 6x-2x > = 12-2, merge similar items

1. If the value of the algebraic formula 2x-1 / 3 is negative, then the value range of X is () 2. The positive integer solution of the inequality 2-2 (x-1) > 0 is () 3. If the value of the algebraic formula X / 5-5 is not greater than the value of the algebraic formula X / 2-3, then the value range of X is () one variable one degree inequality

If the value of the algebraic formula 2x-1 / 3 is negative, then the value range of X is () (2x-1) / 3 & lt; 0, and the positive integer solution of X & lt; 1 / 2 inequality 2-2 (x-1) & gt; 0 is () 2 & gt; 2 (x-1), and the positive integer solution is x = 1. If the value of the algebraic formula X / 5-5 is not greater than the value of the algebraic formula X / 2-3, then the value range of X is

When x satisfies what condition, the value of algebraic formula 3-3 / 2x is not less than 5 / 8-4x-3 / 6

The answer is: x = 0

When x is a negative integer, the value of the algebraic formula X / 2-4x + 3 / 11 is not less than - 0.5
This is a practical question, not a blank question

All negative integers

If we know 16x-8x + 1 = 0, then the value of 8x + 1 is 0___ When x=___ The value of the algebraic formula x + 4x + 4 is the smallest

From the equation 16x-8x + 1 = 0, x = 1 / 4, so 8x + 1 = 3
X + 4x + 4 = (x + 2) ^ 2, when x = - 2, the function value is the minimum

No matter what value x takes, the value of the algebraic formula 2x ^ 2-4x-1 is always greater than that of x ^ 2-2x-4

2x²-4x-1=2(x²-2x+1)-3=2(x-1)²-3
x²-2x-4=(x-1)²-5
Because, no matter what the value of X is, (x-1) &# 178; ≥ 0
So there are always: 2 (x-1) & # 178; - 3 > (x-1) & # 178; - 5
That is, no matter what value x takes, the value of the algebraic formula 2x & # 178; - 4x-1 is always greater than that of X & # 178; - 2X-4

No matter what value x takes, is the value of the square of the algebraic formula 2x-4x-1 necessarily greater than the square of x-2x-4

2x2-4x-1>x2-2x-4
x2-2x+3>0
x2-2x+1>-2
(x-1)^2>-2
We can see that the above formula holds for any value of X
So if x takes any value, the square of the algebraic formula 2x-4x-1 must be greater than the square of x-2x-4

No matter what value x takes, the value of the algebraic formula 2x ^ 2-4x + 5 is always positive

2x²-4x+5
=2x²-4x+2+3
=2(x-1)²+3
The square is greater than or equal to 0
SO 2 (x-1) & sup2; ≥ 0
SO 2 (x-1) & sup2; + 3 ≥ 3 > 0
So no matter what value x takes, the value of the algebraic formula 2x ^ 2-4x + 5 is always positive

It is proved that no matter what value x takes, the value of the algebraic formula - 2x ^ 2 + 4x-7 is always less than 0

-2x²+4x-7
=-2(x²-2x+1)-5
=-2(x-1)²-5;
∵ (x-1) &# (178; ≥ 0) is tenable;
The results show that - 2 (x-1) &# 178; - 5; ≤ - 5 ＜ 0 is tenable
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If a and B are opposite to each other, then the value of three seventh a plus three seventh B-5 is equal to?

A and B are opposite numbers, a + B = 0
Three seventh a plus three seventh B-5
=3/7(a+b)-5
=0-5
=-5