It is known that the lengths of the two right sides of a right triangle are 3cm and 4cm, then the circumcircle radius of the triangle is____ cm. What is it? Look carefully!

two point five
According to the groove theorem, the hypotenuse of the right triangle must be 5. It is also a diameter of the circle, so the radius is half of 5

In a right triangle, if the lengths of two right angles are 3cm and 4cm, what is the height of the hypotenuse?
It's for the height on the hypotenuse! It's not for the hypotenuse!

The hypotenuse is 5cm,
S triangle ABC = (1 / 2) * 3 * 4 = 6
The same is true
S triangle ABC = (1 / 2) * 5 * x (x is the height on the hypotenuse)
So x = 6 * (2 / 5) = 12 / 5 cm

In a right triangle, if the length of two right sides is 3cm and 4cm, what is the height of the third side?
As shown in the picture

Pythagorean theorem
Hook 3 strands 4 strings 5
Area = 3 * 4 / 2 = 6
The area is 5 * H / 2
So high = 2.4

It is known that the lengths of the two right sides of a right triangle are 3cm and xcm, and the length of the hypotenuse is YCM. The analytic function of Y with respect to X and the value range of the independent variable X are obtained

Because the triangle is a right triangle, that is: y * y = 3 * 3 + X * x (x0, Y0) (1) \ \ x0d, and because of the basic theorem of the triangle, the sum of the two sides is greater than the third side, that is: 3 + XY (2) \ \ x0d. According to formula (1) and formula (2): \ \ x0dy = radical (9 + X * x) \ \ x0d (3 + x) y = radical (9 + X * x) \ \, The analytic expression of the function of Y with respect to X is y = root (9 + X * x) (x0) \ \ x0d, where x0 is the value range of the independent variable x

For a right triangle, the two right sides are 5cm and 12cm respectively, and the hypotenuse is 13cm?

You can use area to find 5 * 12 * 0.5 = 13 * h * 0.5 (H stands for high). The answer is 60 / 13

In RT △ ABC, if the angle c equals 90 degrees, C equals 12, and tanb equals three-thirds of the root sign, then the area of △ ABC
A 36 times root 3 B18 times root 3 C16 D18

BBBBBBBBBBBBBBBBBBBBBBBB
tanB=√3/3,∴B=30°
C=90°,∴b=c/2=6
a=6√3
S=ab/2=18√3

As shown in the figure, in RT △ ABC, CD is the middle line on the hypotenuse ab. given CD = 2, AC = 3, then CoSb=______ ．

∵ in RT △ ABC, CD is the middle line on the hypotenuse AB, CD = 2, ∵ AB = 2CD = 4. According to Pythagorean theorem, BC = AB2 − ac2 = 42 − 32 = 7, ∵ CoSb = bcab = 74, so the answer is: 74

As shown in the figure, in RT △ ABC, CD is the middle line on the hypotenuse ab. given CD = 5 and AC = 6, then the value of tanb is ()
A. 45B. 35C. 34D. 43

According to Pythagorean theorem, BC = AB2 − ac2 = 102 − 62 = 8, tanb = ACBC = 68 = 34

As shown in the figure, in RT △ ABC, AB is the hypotenuse, P is on the central line CD, AC = 3, BC = 4
As shown in the figure, in RT △ ABC, ∠ ACB = 90 °, AC = 3, BC = 4, CD is the middle line of hypotenuse AB, P is a moving point on CD (not coincident with C and D), PC = x, s △ PAB = y. find the functional relationship between y and X and write out the range of independent variables

The perpendicular ce of hypotenuse AB from point C intersects AB at e (that is, the height of hypotenuse RT △ ABC)
The perpendicular PF of the hypotenuse AB from point P intersects AB with F (that is, the height of AB on △ PAB side)
Because in RT △ ABC, ∠ ACB = 90 °, AC = 3, BC = 4, so AB = 5 (Pythagorean theorem)
Because CD is the middle line on the hypotenuse of RT △ ABC, CD = AB / 2 = 2.5
Because △ ACD ∽ ABC, AC / AB = CE / BC, that is, 3 / 5 = CE / 4, CE = 12 / 5
Because △ DPF ∽ DCE, PF / CE = Pd / CD
Let PC = x, then PD = cd-x = 2.5-x, so pf = PD × CE / CD = (2.5-x) × 12 / (2.5 × 5) = (30-12x) / 12.5
So s △ PAB = y = ab × PF / 2 = 5 × (30-12x) / 12.5 △ 2
Namely: y = 1.2 (5-2x)
Because point P does not coincide with C and D, so: 6 ＞ 1.2 (5-2x) ＞ 0 (6 is the area of △ ABC)
The solution is 0 ＜ x ＜ 2.5

In RT triangle ABC, angle c = 90 °, SINB = 3 / 5, a = 6, then Tana=___ (more detailed)

sinB=3/5
Let B = 3x, then C = 5x, from Pythagorean theorem we get (3x) ^ 2 + 6 ^ 2 = (5x) ^ 2, then x = 3 / 2, B = 9 / 2
tanA=a/b=6/(9/2）=4/3

It is known that the lengths of the two right sides of a right triangle are 3cm and 4cm, then the circumcircle radius of the triangle is____ cm. What is it? Look carefully!