The known function f (x) = x ^ 2 + alnx

The known function f (x) = x ^ 2 + alnx

If G (x) = f (x) + 2 / X is a monotone increasing function on [1, positive infinity], find the value range of real number a, so: G '(x) = 2x + (A / x) - (2 / x ^ 2) = (2x ^ 3 + AX-2) / x ^ 2 / x0d, because x ∈ [1, + ∞), so: x ^ 2 ＞ 0, then let H (x) = 2x ^ 3 + AX-2 / x0d

The known function f (x) = alnx-x ^ 2
Let g (x) = f (x) + ax, if y = g (x) is not monotone in the interval (0,3), find the value range of A

g'(x)=f'(x)+a
=a/x -2x +a
=0
We get - 2x ^ 2 + ax + a = 0
X1 = (- A + radical (a ^ 2 + 8a)) / (- 4) = A / 4-radical (a ^ 2 + 8a) / 4
X2 = (- a-radical (a ^ 2 + 8a)) / (- 4) = A / 4 + radical (a ^ 2 + 8a) / 4
0

Given the function f (x) = X-2 / x + 1-alnx, a ＞ 0, (I) the monotonicity of the discussion; (II) let a = 3, find the range on the interval {1, e square}. The middle e = 2.7182

f(x)=x-2/x+1-alnx
f'(x)=1+2/x²-a/x
Let f '(x) = 0
We get (X & # 178; - ax + 2) / X & # 178; = 0
△=a²-8
(I) when △ 0 increases monotonically
When x