As shown in the figure, C is the midpoint of line AB, and point D is the length of line AB, which is 3:2. Given CD = 7cm, find the length of ab

As shown in the figure, C is the midpoint of line AB, and point D is the length of line AB, which is 3:2. Given CD = 7cm, find the length of ab

∵ C is the midpoint of segment AB ∵ AC = BC = 12ab ∵ d the length of segment AB is 3:2 ∵ ad = 35ab ∵ DC = 35ab-12ab = 110ab ∵ CD = 7cm ∵ 110ab = 7cm ∵ AB = 70cm

Given that M = the square of 2A + 3ab-2a-1, n = the square of a + AB-1, if the value of 3 (m-2n) has nothing to do with the value of a, find the value of B

3(M-2N)
=3[2a^2+3ab-2a-1-2(a^2+ab-1)]
=3[2a^2+3ab-2a-1-2a^2-2ab-2]
=3[ab-2a-3]
=3(b-2)a-9
The conclusion has nothing to do with a. the coefficient before a is 0,
That is, B-2 = 0,
b=2.

It is known that M = 2A square + 3ab-2a-1, n = a square + AB-1. (2) if the value of 3 (m-2n) is the same as that of A
It is known that M = 2A square + 3ab-2a-1, n = a square + AB-1
(2) If the value of 3 (m-2n) has nothing to do with the value of a, try to find the value of B

M = 2A ^ 2 + 3ab-2a-1 n = a ^ 2 + AB-1 if 3 (m-2n) ignores the value of a, get the value of B

m-2n=2a^2+3ab-2a-1-2(a^2+ab-1)
=2a^2+3ab-2a-1-2a^2-2ab+2
=ab-2a+1
-->So B = 2

(1) Given a + B = 4, ab = 1, find the value of 2A + 3AB + 2B; (2) if the square of X + 3x + 5 is 7,
Find the value of the square-2 of the polynomial 9x + 3x;

a+b=4,ab=1,
2a+3ab+2b
=2(a+b)+3ab
=2×4+3
=11
The square of X + 3x + 5 = 7
We get x ^ 2 + 3x = 2
The square of 9x + 3x - 2
=3(x^2+3x)-2
=3×2-2
=4

Let's know the quadratic power of a = a + the quadratic power of B - 3ab-2, the quadratic power of B = B - the quadratic power of a - AB + 1, and find 2A + B

If the cubic power of AB is known to be 3, then the algebraic expression AB (cubic power of ab-b)=

Known AB & # 178; = 3
Then AB (AB & # 179; - b) = A & # 178; B & # 8308; - AB & # 178; = (AB & # 178;) - # 178; - AB & # 178; = 3 & # 178; - 3 = 6
If you don't understand, please hi me, I wish you a happy study!

Given the quadratic power of a-Ab = 8, the quadratic power of ab-b = - 4, then the quadratic power of A-B = what? The quadratic power of a-2ab + B = what
Come on, I'm in a hurry

A^2-AB=8,AB-B^2=-4
A^2-B^2=(A^2-AB)+(AB-B^2)=8-4=4
A^2-2AB+B^2=(A^2-AB)-(AB-B^2)=8-(-4)=12

Given the quadratic power of a + AB = - 3, the quadratic power of AB + B = 7, try to find the value of the quadratic power of a + 2Ab + B and the quadratic power of a-b

Because a & # 178; + AB = - 3, AB + B & # 178; = 7
1）
a²+ab+ab+b²=-3+7
a²+2ab+b²=4
2）
a²+ab-（ab+b²）=-3-7
a²-b²=-10

If a's second power + AB = negative 10, B's second power + AB = 16, then a's second power + 2Ab + B's second power = what? A's second power - B's second power = what?

a²+ab=-10
b²+ab=16
Two formula addition
a²+2ab+b²=6
Subtraction of two formulas
a²-b²=-26