ABCD represents four different natural numbers and a × B × C × d = 2709, then what is the maximum value of a + B + C + D

ABCD represents four different natural numbers and a × B × C × d = 2709, then what is the maximum value of a + B + C + D

Decomposition quality factor
2709=3*3*7*43
You can think of a factor as 1
Because ABCD represents four different natural numbers
So combine the two smallest factors
4.9.1
So the minimum is 60
Combine 3 with the largest factor
So the four factors are 1.3.7.129
The maximum is 140

Given that (A / 1 + B / 1 + C / 1 + D / 1) + 36 / 1 + 45 / 1 = 1 and a, B, C, D are four continuous natural numbers, find the value of a + B + C + D?
quickly

Let a, B, C, d be x, x + 1, x + 2, x + 3
1/x+1/(x+1)+1/(x+2)+1/(x+3) +1/36+1/45=1
1/x+1/(x+1)+1/(x+2)+1/(x+3)＝19/20
The solution is: x = 3
So a = 3, B = 4, C = 5, d = 6
a+b+c+d=3+4+5+6=18

There are four natural numbers ABCD. The least common multiple of a and B is 36. The least common multiple of C and D is 90. What is the least common multiple of ABCD

The least common multiple of 36 and 90 = 180
The least common multiple of ABCD's four numbers is 180