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f(x)=xe^x 則: f'(x)=(x)'(e^x)+(x)(e^x)' f'(x)=(x+1)e^x 関数f(x)が(-∞,-1)のときに減少し、(-1,+∞の上でインクリメントすると、 関数f(x)には最小値があり、最小値はf(-1)=-1/eです。
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