A = 2 * 2 * 3, B = 2 * 3 * 5, what is the greatest common factor and the least common multiple of a and B?

Greatest common factor: 2 * 3 = 6
Least common multiple: 2 * 2 * 3 * 5 = 60
PS: the greatest common factor is the product of the prime factors shared by two numbers
The least common multiple is the product of the largest number of all prime factors among the factors of two numbers

A = 2 × 3 × N2, B = 3 × N3 × 5, (n is prime), then the greatest common divisor of a and B is The least common multiple is ．

A = 2 × 3 × N2, B = 3 × N3 × 5 (n is prime), so the greatest common divisor of a and B is 3 × N2; the least common multiple of a and B is 2 × 3 × N3 × 5; so the answer is: 3 × N2, 2 × 3 × N3 × 5

What is the greatest common factor and the least common multiple of a and B

The greatest common factor of a and B is (the square of 2) 2 × 2 × 7 = 28
The least common multiple is 28 × 3 × 2 = 168

A = 2 times 3 times N, B = 3 times 5 times N times m (N and m are different prime numbers greater than 5). The greatest common factor of a and B is () and the least common multiple is ()
Hope to give the thinking process.

A = 2 times 3 times N, B = 3 times 5 times N times m (N and m are different prime numbers greater than 5). The greatest common factor of a and B is (3n), and the least common multiple is (2x3x5xnxm)

In the circuit shown in the figure, the resistance value of resistance R1 is 20 Ω. Close switch s, the indication value of ammeter A1 is 0.6A, and that of ammeter A2 is 0.4A. Calculate: (1) power supply voltage; (2) indication value of ammeter a; (3) resistance value of resistance R2

It can be seen from the circuit diagram that resistance R1 and resistance R2 are connected in parallel, ammeter a measures the current of main circuit, ammeter A1 measures the current of R1 branch, and ammeter A2 measures the current of R2 branch; (1) ∵ the voltage at both ends of each branch in the parallel circuit is equal, ∵ according to Ohm's law, the voltage of power supply: u = U1 = i1r1, R1 = 0.6A × 20 Ω = 12V; (2) ∵ the main circuit current in the parallel circuit is equal to the sum of all branch currents, The indication of ammeter A: I = I1 + I2 = 0.6A + 0.4A = 1A; (3) the resistance value of resistance R2: R2 = ui2 = 12v0.4a = 30 Ω. Answer: (1) the power supply voltage is 12V; (2) the indication of ammeter A is 1A; (3) the resistance value of resistance R2 is 30 Ω

If the solution of the equation (K + 2) x & # 178; + 4kx + 7 of X is a natural number, then the value of integer k is_ It is known that the absolute value + 3 = 0 of equation 5x (M + 2) is a linear equation of one variable with respect to x, then M=_ .

If the solution of the equation (K + 2) x & # 178; + 4kx + 7 = 0 of X is a natural number, then the value of integer k is__ 3__ Given that equation 5x ^ m + 2 + 3 = 0 is a linear equation of one variable with respect to x, then M=_ -1__ .

Is there a "J" in the resistance unit? What is the resistance converted into ohm?

No, for example, 45 Ω J represents 45 Ω, J represents plus or minus 5%, and the error sign is

The result of simplifying 2 / 1 of X-1 divided by 1 / 1 of X-1 is

2/(x+1)(x-1) ÷1/(x-1)
=2/(x+1)(x-1)×(x-1)
=2/(x+1)

As shown in the figure, the rated current of the following electrical appliances closest to 4a is ()
A. Household refrigerator B. television C. energy saving lamp D. electric pressure cooker

The rated voltage of household appliances are all 220 v. according to our understanding of the electric power of appliances and the variant formula of the electric rate formula I = Pu, the electric power of the four appliances a and the household refrigerator is about 200 W. according to I = Pu, the electric power of the refrigerator is about 1A, so a is wrong; B and the electric power of the TV is about 100 W

A = 2 * 2 * 3, B = 2 * 3 * 5, what is the greatest common factor and the least common multiple of a and B?