A = the square of 2x3xn, B = the third power of 3XN, X5 (n is prime), (a, b) =? What is the least common multiple of a, B? Explain the reason, not just the result!

A = the square of 2x3xn, B = the third power of 3XN, X5 (n is prime), (a, b) =? What is the least common multiple of a, B? Explain the reason, not just the result!


Some factors of AB are 3 and N & sup2;
So (a, b) = 3 × n & sup2;
All the factors of AB have the highest order, which is the least common multiple [a, b]
So [a, b] = 2 × 3 × n & sup3; × 5



How to calculate the least common multiple of prime number? Does prime number have a common divisor
A, B, C and d go to the library every five days, B every 11 days, C every 17 days and D every 29 days. They met in the library on May 18 and asked when the next meeting was,,,


The least common multiple of two prime numbers is their product. For example, the least common multiple of 23 is 6, 79 is 632



Physics of Grade 8: if the electric lamp marked "220 V, 25 W" is connected to the home circuit, and it is powered on for 1 hour, the work done by the current is () J, please explain in the following formula


Just convert the time to Si seconds,
Work = Pt = 25W * 1H = 25W * 3600s = 90000w · s = 90000j



62.5*0.16+2640*0.0625+5.2*6.25+0.0625*20


This problem is easy to solve only if you mention the common factor
Then the original formula = 6.25 * 1.6 + 6.25 * 26.4 + 6.25 * 5.2 + 6.25 * 0.2
=6.25*(1.6+26.4+5.2+0.2)
=6.25*33.4=208.75



Voltage power supply is 6V, resistance R1 = 50 ohm, R2 is a sliding rheostat,
When the slide slide is at the middle point, the indication of the ammeter is 0.36A. Can the sliding rheostat be adjusted to 0? Why? (resistor R1 and R2 are in parallel with the resistor and the ammeter is on the trunk road)


When the slide is in the middle point
I1=U/R1=6/50=0.12A
I2=I-I1=0.36-0.12=0.24A
R2=U/I2=6/0.24=25Ω
The total resistance of the sliding rheostat is 50 Ω
If R1 and R2 are connected in parallel and the sliding rheostat R2 is adjusted to 0, then the total resistance of R1 and R2 is zero (short circuit), and the power supply current (current of ammeter) will be very large, which will burn out the power supply and ammeter



25 * (- 0.125) * (- 4) * (- 4 / 5) * (- 8) * 5 / 4 simple algorithm


=[25*(-4)]*[(-0.125*(-8)]*[(-4/5)*(5/4)]
=-100*1*(-1)
=100



In order to design a shunt circuit, it is required to enlarge the range of 5mA ammeter by 5 times


1) 1000 Ω * 0.005 a = 5 V
2) 5 ma * 5 = 25 ma - 5 Ma = 20 mA
3) 5 V / 20 mA = 250 Ω
The shunt resistance is 250 ohm



0,3,8,15,?,35


24.
0+3=3
3+5=8
8+7=15
15+9=24
24+11=35



How to convert feet to meters, pounds to kilograms


1 pound = 16 ounces = 0.4536 kg unit attribute: belongs to the mass unit no example: Page Main comment: my weight is 118 Jin, change into pounds is 130 pounds, I weigh 130 pounds, don't say I'm a monkey in the future! 11 feet = 12 inches = 0.3048 meters, length 1 km = 0.621 mile 1 meter



Physics knowledge in life
How many V of power supply voltage, power supply positive and negative pole phase, can produce electric spark
Electric spark can ignite and find gunpowder


Do not connect! Keep a distance! When the voltage reaches about 650V! The voltage can break down the air between the wires... Form an electric spark! At this time, the air around the wires is also ionized!
If you want to ignite the powder, you don't have to have an electric spark. Just use a heated resistor! You can reach the temperature!
Advice! Too dangerous! Don't do it