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At the same time, the two brothers walk from a and B, with a speed of 12.5km per hour and B speed of 10km per hour. They meet at a distance of 3.25km from the midpoint to seek the distance
@"Science tutor" answers questions for you
The distance difference is 3.25 * 2 = 6.5km
The speed difference is 12.5-10 = 2.5 km / h
The meeting time is 6.5 / 2.5 = 2.6 hours
The distance between a and B is (12.5 + 10) * 2.6 = 58.5km
A: the distance between a and B is 58.5km
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Party A and Party B set out from a and B at the same time and walked towards each other. Six hours later, Party A and Party B met at a distance of 12 km from the midpoint (the meeting place was close to b),
B: 42 kilometers per hour, a: how many kilometers per hour? Tell me what to get at each step
When meeting, a has more lines than B: 12 × 2 = 24 km
A has more rows per hour than B: 24 △ 6 = 4 km
A: 42 + 4 = 46 km per hour
Party A and Party B set out from ab at the same time and went opposite each other. When they met, they were 48 kilometers away from A. after meeting, they continued to move forward and arrived
To solve the equation
How many kilometers is the distance between a and B when they meet for the second time 94 kilometers away from a?
The distance ratio is equal
Let X be the total length
Then:
The first time a met, he walked 48 kilometers, and B walked x-48 kilometers
A walked (x-48 + x-94) kilometers in the second encounter, B walked 94 kilometers
So:
48/(x-48)=(x-48+x-94）/94
Namely: 48 * (2x-142) = 94 * (x-48)
x=1152
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