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A and B two cars respectively from AB two opposite, after meeting a car in 4 hours to B, B car 1 hour to a, a and B two car speed ratio is
The speed ratio of a and B vehicles is 1:2
The two cars meet in 2 hours, a driving for 6 hours, B driving for 3 hours
Let the encounter time be t hours
t[1/(t+4）+1/(t+1)]=1
T = ± 2 (take positive value)
It takes 15 hours for car a to go from city a to city B, and 12 hours for car B to go from city B to city A. how many hours do the two cars meet
Car a completes 1 / 15 of the whole journey per hour, and car B completes 1 / 12 of the whole journey per hour
When the two vehicles run in opposite directions at the same time, the time spent when they meet is: 1 / (1 / 15 + 1 / 12) = 60 / 9 = 20 / 3 (hours)
A: the two cars meet in 20 / 3 hours
Car a and car B travel from a and B at the same time, and they can meet in 10 hours. Now car a is 1060 kilometers away from city B one hour after it is released from city a, and car B is 1060 kilometers away from city B
One hour later, it's 1030 kilometers away from city A. how many kilometers will the two cities get together? Thank you in advance
2090 km, please ask me for details
A and B start from city a and city B at the same time and travel in opposite directions. The speed ratio of a and B is 5:4. When they meet, they are 48 kilometers away from the destination. How many kilometers is the distance between the two cities?
When meeting, 5 / (5 + 4) of the whole course of a line is 5 / 9, and 4 / 9 of the whole course of B line
The midpoint is 1 / 2.48 km of the whole journey, corresponding to 5 / 9-1 / 2 = 1 / 18
The whole course is 48 / (1 / 18) = 864 km
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