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After 12 hours, they meet and continue to drive at the same speed. After 10 hours, car a arrives at place B and car B returns How many kilometers is the difference between AB and ab by 10 kilometers
AB: 10 ÷ (12-10) X12 = 60 (km)
Two vehicles a and B respectively travel from ab at the same time. After meeting for three hours, the two vehicles continue to move forward. The speed of vehicle B increases by 20 kilometers per hour,
It takes another 1.8 hours for car a to arrive at B. at this time, car B is 108 kilometers away from a,
The answer is 200 or 360?
Car distance before meeting: car distance after meeting = 3:1.8 = 5:3
After the meeting, the distance is 3 hours
Original speed of car a: original speed of car B = distance ratio before and after meeting = 5:3
Then the time ratio of the whole process
A: B = 1 / 5:1 / 3 = 3:5
The whole course of B line = (3 + 1.8) △ 3 × 5 = 8 hours
If vehicle B does not increase its speed, it will be 108 + 1.8 × 20 = 144 km away from the ground
Speed of vehicle B = 144 ÷ (8-4.8) = 45 km / h
Speed of car a = 45 △ 3 × 5 = 75 km / h
A and B travel from a and B, which are 27 kilometers away from each other. They meet in three hours. If a is x kilometers per hour faster than B, find the speed of a and B
Let B's speed be x km / h, then the speed of acceleration is () km / h; the corresponding equation is listed (); the solution shows that a's speed is () km / h, B's speed is () km / h
The velocity of a is 2x, equation 3 (x + 2x) = 27, the velocity of a is 6, and the velocity of B is 3
A and B travel from a and B at the speed of 3 km and 5 km per hour respectively. After meeting, they continue to move forward. If a reaches B from the meeting point for a total of 4 hours, then a and B are far away______ Kilometers
4 × 3 / 5 = 12 / 5 = 2.4 (hours); 2.4 × (3 + 5) = 2.4 × 8 = 19.2 (kilometers); so the answer is: 19.2
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