The distance between the two places is 460 km. Two passenger and freight cars leave from the two places at the same time. After 4 hours of meeting, the known passenger cars travel 62 km per hour and the freight cars 62 km per hour How many meters is it

The distance between the two places is 460 km. Two passenger and freight cars leave from the two places at the same time. After 4 hours of meeting, the known passenger cars travel 62 km per hour and the freight cars 62 km per hour How many meters is it

460÷4-62=53
The truck runs 53 kilometers per hour

The passenger car and the freight car are facing each other from a and B at the same time. They meet 95 kilometers away from B. after meeting, the two cars continue to move forward
After arriving at a and B, the two vehicles immediately return at the same speed, and then meet 25 kilometers away from A. how many kilometers are there between a and B?

Let the distance between a and B be x, and the speed of bus and train be a and B respectively
According to the principle of equal time, when two cars meet twice, the time they spend should be equal,
Then, when we first met, the equation was:
95/b=(x-95)/a
The equation of the second meeting is as follows:
(x+25)/b=(2s-25)/a
The two equations are simplified
(x-95)*(x+25)=95*(2x-25)
Rearrangement:
x*(x-260)=0
Solution
x=260
So the distance between a and B is 260 kilometers