When a and B start from a and B, the speed ratio of a and B is 5:4. After meeting, the speed of a decreases by 20%, and the speed of B increases by 20%. So when a arrives at B, B is still 10 kilometers away from a, so how many kilometers is the distance between a and B?

When a and B start from a and B, the speed ratio of a and B is 5:4. After meeting, the speed of a decreases by 20%, and the speed of B increases by 20%. So when a arrives at B, B is still 10 kilometers away from a, so how many kilometers is the distance between a and B?


The arithmetic solution is as follows:
After meeting, the speed ratio of a and B is 5 × (1-20%): 4 × (1 + 20%) = 5:6
When meeting, B walked the whole journey 4 (5 + 4) = 4 / 9
So after meeting, a went to B, and a took 4 / 9 of the whole journey
So after meeting, a goes to B, and B goes the whole way 4 / 9 △ 5 × 6 = 8 / 15
So B took a total of 4 / 9 + 8 / 15 = 44 / 45
So the distance between AB and ab is 10 △ 1 / 45 = 10 △ 1 / 45 = 450 km
A: AB is 450 kilometers away



The speed ratio of car a and car B is 5:4, and the speed of car a increases by 20% after meeting,
The speed of car B increases by 25%, so that when car a arrives at place B, car B is still 15 kilometers away from place a


@"Science tutor" answers questions for you. After meeting, the speed ratio of the two cars is 5 * (1 + 20%): 4 * (1 + 25%) = 6:5. After meeting, car a runs 4 / (5 + 4) = 4 / 9 of the whole journey. When car a arrives at place B, car B runs (4 / 9) * (5 / 6) = 10 / 27 of the whole journey. When car a arrives at place B, car B still has 1-4 / 9 of the whole journey



It is known that car a is 20 kilometers slower than car B per hour. The speed ratio of car a and car B is 5:7. How far is the distance between AB and car B?


When 20 × 6 = 120 km, car a takes less distance than car B
When the time is fixed, the express delivery ratio is the distance ratio. When the two cars meet, the distance ratio is 5:7
That is to say, car a takes the whole journey: 5 / (5 + 7) = 5 / 12
Car B took the whole journey: 7 / (5 + 7) = 7 / 12
Car a is short: 7 / 12-5 / 12 = 1 / 6
Whole journey (distance between two places): 120 △ 1 / 6 = 720 (km)



The two cars of a and B are facing each other from ab at the same time, and they meet at 5km away from the midpoint. It is known that the speed of car a is 6 / 7 of that of car B, and how many kilometers are there between a and B


The distance between the two places is 2x km,
Because the speed of car a is 6 / 7 of that of car B, the distance of car a is 6 / 7 of that of car B
So (X-5) / (x + 5) = 6 / 7
So x = 65
So 2x = 130 km, that is, the distance between the two places is 130 km