To 50 ml of 18 mol/L concentrated sulphuric acid, add sufficient copper flakes to heat to produce a volume of SO2 gas under standard conditions,=20.16, or =10... To 50 ml of 18 mol/L concentrated sulfuric acid, add a sufficient amount of copper sheet to heat to produce a volume of SO2 gas in the standard case,=20.16,=10.08, or >10.08 and To 50 ml of 18 mol/L concentrated sulphuric acid, add sufficient copper flakes to heat to produce a volume of SO2 gas under standard conditions,=20.16, or =10... To 50 ml of 18 mol/L concentrated sulfuric acid, add a sufficient amount of copper sheet to heat to produce a volume of SO2 gas in the standard case,=20.16,=10.08, or >10.08, and To 50 ml of 18 mol/L concentrated sulphuric acid, add sufficient copper flakes to heat to produce a volume of SO2 gas under standard conditions,=20.16, or =10... To 50 ml of 18 mol/L concentrated sulphuric acid, add a sufficient amount of copper sheet to heat to produce a standard volume of SO2 gas,=20.16,=10.08, or >10.08 and

To 50 ml of 18 mol/L concentrated sulphuric acid, add sufficient copper flakes to heat to produce a volume of SO2 gas under standard conditions,=20.16, or =10... To 50 ml of 18 mol/L concentrated sulfuric acid, add a sufficient amount of copper sheet to heat to produce a volume of SO2 gas in the standard case,=20.16,=10.08, or >10.08 and To 50 ml of 18 mol/L concentrated sulphuric acid, add sufficient copper flakes to heat to produce a volume of SO2 gas under standard conditions,=20.16, or =10... To 50 ml of 18 mol/L concentrated sulfuric acid, add a sufficient amount of copper sheet to heat to produce a volume of SO2 gas in the standard case,=20.16,=10.08, or >10.08, and To 50 ml of 18 mol/L concentrated sulphuric acid, add sufficient copper flakes to heat to produce a volume of SO2 gas under standard conditions,=20.16, or =10... To 50 ml of 18 mol/L concentrated sulphuric acid, add a sufficient amount of copper sheet to heat to produce a standard volume of SO2 gas,=20.16,=10.08, or >10.08 and

Cu+2H2SO4(concentrated)==heating ==CuSO4+SO2↑+2H2O
Only half of the S is restored
N (H2SO4)=18*0.05=0.9mol
So most n (SO2)=0.45 mol
V (SO2)=22.4*0.45=10.08L
However, the concentrated sulfuric acid can not completely react, so it is less than 10.08L

When copper reacts with concentrated sulfuric acid, how many mol? Cu+2H2SO4=CuSO4+2H2O+SO2

0.2Mol
The amount of concentrated sulfuric acid involved in the reaction is determined according to the equation because 0.2 mol of electrons are transferred, i.e.0.1 mol of Cu is involved in the reaction

0.2Mol
The amount of concentrated sulfuric acid involved in the reaction ise.0.1 mol of Cu is involved in the reaction, the amount of concentrated sulfuric acid involved in the reaction is determined according to the equation

0.2Mol
The amount of concentrated sulfuric acid involved in the reaction.e.0.1 mol of Cu is involved in the reaction, the amount of concentrated sulfuric acid involved in the reaction is determined according to the equation