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The seventh power of factorization 36 minus the twelfth power of 6 can be divisible by 35
36^7-6^12=36^7-36^6=36^6(36-1)=35*36^6
Use factorization to prove that the 7th power of 36 minus the 12th power of 6 can be divisible by 140 36 To the 7th power minus 6 to the 12th power =6 To 14 to 6 to 12 =6 To the 12th power ×(36-1) =10Th power of 6×4×9×35 =10Th power of 140×9×6 The 7th power of 36 minus the 12th power of 6 can be divided by 140 But it is not clear why the 12th power of =6 to the 14th power to the 6th power ×(36-1)?
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