If the absolute value of the square of (a +1)+b-2=0, then the third power of the 2009 power of a -b =

If the absolute value of the square of (a +1)+b-2=0, then the third power of the 2009 power of a -b =

Solution: because (a+1)^2 b-2|=0, a+1=0,|b-2|=0, a=-1, b=2, a^2009-b^3=(-1)^2009-2^3=-1-8=-9.

What is the absolute value of -1 multiplied by the minus half of the minus second power, plus the root minus the 0th power of π, plus 1-sin 60? 0Th power of (root minus π) What is the absolute value of -1 multiplied by the minus half of the minus second power, plus the root minus the 0th power of π, plus 1-sin 60? (Root minus π) to the 0th power What is the absolute value of the -2009 power of -1 multiplied by the negative second power of minus one-half, plus the 0 power of root minus π, plus 1-sin 60? 0Th power of (root minus π)

(-1)^2009=-1
(-1/2)^(-2)=(-2)^2=4
(Root 3-pi)^0=1
Sin 60= root 3/2
(-1)*4+1+1-Root 3/2
=2-Nos.3/2
Its absolute value is 2+root 3/2

(-1)^2009=-1
(-1/2)^(-2)=(-2)^2=4
(Root 3-pi)^0=1
Sin 60= root 3/2
(-1)*4+1+1-Root 3/2
=2-Nos.3/2
Its absolute value is 2+3/2