If a is the largest negative integer, find the 2001 power of a + the 2002 power of a + the 2003 power of a + the 2010 power of...+ a

2003 Power of 2000 and 2001 power and end of 2002

The single digit of the 2003 power of 2000 is:0
The single digit of the Nth power of 2 is 2,4,8,6 cycles
2001/4=500...1, The remainder is 1, indicating that the 2001 power of 2002 is 2
Therefore, the sum of the 2003 side of 2000 and the 2001 side of 2002 is:0+2=2

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