Given that e is the unit vector, vector of a =(root number 3-1, root number 3+1), and the angle between e vector and a vector is 45°, then e vector is equal to? Given that e is the unit vector, the vector of a =(root number 3-1, root number 3+1), and the angle between e vector and a vector is 45°, then e vector is equal to?

Given that e is the unit vector, vector of a =(root number 3-1, root number 3+1), and the angle between e vector and a vector is 45°, then e vector is equal to? Given that e is the unit vector, the vector of a =(root number 3-1, root number 3+1), and the angle between e vector and a vector is 45°, then e vector is equal to?

0

Given vector a vector =(-1, root number 3), vector b =(root number 3,-1), what is the angle between vector a and vector b Given vector a =(-1, root number 3), vector b =(root number 3,-1), what is the angle between vector a and vector b

Cos =(a vector multiplied by b vector)/(the module of a vector multiplied by the module of b vector)
=(-1 Multiplied by root 3+ root 3 multiplied by -1)/{[(root -1) square +(root 3) square] multiplied by [(root 3) square +(-1) square ]}=- root 3/2
The angle between vector a and vector b is equal to 120°

Given vector a=(root number 3,1), b is a unit vector not parallel to the x-axis, and ab=root number 3, then b equals Please elaborate, thank you! Given vector a=(root number 3,1), b is a unit vector that is not parallel to the x-axis, and ab=root number 3, then b Please elaborate, thank you!

Let b=(x, y)
Because b is a unit vector that is not parallel to the x-axis
So y is not equal to 0, and x^2+y^2=1
Ab = root 3*x+y = root 3
So y = root 3*(1-x)
Y^2=3(1-x)^2=3-6x+3x^2
So 1=x^2+y^2=4x^2-6x+3
So 4x^2-6x+2=0
2X^2-3x+1=0
(2X-1)(x-1)=0
So x =0.5 or x =1
And because when x=1, y = root 3*(1-x)=0, does not meet the requirement that y is not equal to 0(where b is a vector that is not parallel to the x-axis)
So x =0.5=1/2 y = root 3*(1-x)=(root 3)/2
So b=(1/2,(root 3)/2)

If the angle between vector b and vector a=(1,2) is 180 degrees, and the film length of vector b is equal to 3 times the root number 5, what is the vector b?

Because the angle between vector b and vector a=(1,2) is 180 degrees, it is assumed that vector b is (-X,2X) and X >0.
The film length of b is equal to 3 times the root number 5
The square of the film of b is:(-X squared)+(2X) squared is 5*(X squared)
=3 Times the square of root number 5=45 so X =3
So vector b is (-3,6)

Because the angle between vector b and vector a=(1,2) is 180 degrees, it is assumed that vector b is (-X,2X) and X >0.
The film length of b is equal to 3 times the root number 5
The square of the film of b is:(-X squared)+(2X) squared is 5*(X squared)
=3 Times the square of 5=45 so X =3
So vector b is (-3,6)

Because the angle between vector b and vector a=(1,2) is 180 degrees, it is assumed that vector b is (-X,2X) and X >0.
The film length of b is equal to 3 times the root number 5
The square of the film of b is:(the square of -X)+(the square of 2X) is 5*(the square of X)
=3 Times the square of 5=45 so X =3
So vector b is (-3,6)

If plane vector B and vector A =(−1,2) is 180°, and B=3 5, Then B =() A.(-3,6) B.(3,-6) C.(6,-3) D.(-6,3)

Set

B=λ

A =(-λ,2λ)(λ<0),
∵|

B |=3
5,
∴(-λ)2+(2λ)2=45
∴λ2=9
∵λ<0,∴λ=-3
∴

B=(3,-6)
Therefore, B.

If vectors a, b satisfy |a|=1,|b|=2,|a-b|=2, then |a+b| is equal to A,1B, root 2C, root 5D, root 6

|A-b|=√(a-b)^2=2
(A-b)^2=4
A^2-2ab + b^2=4
1^2-2Ab+2^2=4
Ab=1/2
|A+b|=√(a+b)^2=√(a^2+2ab+b^2)=√(1^2+2*1/2+2^2)=√6
Select D