The sum of the coefficients of the univariate quadratic equation is equal to 0 and the ratio of the two is 1

Let this univariate quadratic equation be y = ax ^ 2 + BX + C, then according to the meaning of the question, we can get: a + B + C = 0 ----------- 1, and because X1 / x2 = 1, that is, X1 = X2, that is: B ^ 2-4ac = O ------ 2. Because X1 * x2 = C / A, X1 + x2 = - B / A, we know that X1 = X2, so: X1 ^ 2 = C / A, 2x1 = - B / A, we can get from these two formulas: (- B / 2a) ^ 2 =

Known algebraic formula 3x ²- If the value of 4x + 6 is 9, then x ²- The value of 4 / 3x + 6 is () Known equation x ²+ BX + a = 0 has a root of - A (a is not 0), then the value of the following algebraic formula is constant (a.ab, B.A / B, C.A + B, d.a-b) Known equation AX ²+ BX + C = 0 (a is not 0) has root 1. If a + B + C = 0, what is x? 2. If A-B + C = 0, what is x? 3. If C = 0, what is x? 4. If 4A + C = 2B, what is x? The first question is to evaluate everyone! Who can give me a process? The third question... The first question is X ²- Four Thirds of the square + 6 excuse me~

1.3x ²- The value of 4x + 6 is 9, so 3x ²- 4X = 3, and X ²- 4/3x+6=1/3（3x ²- 4x+18）=7
2. Equation x ²+ BX + a = 0 has a root of - A (a is not 0), so a ²- AB + a = 0. So divide both sides by a at the same time to get A-B + 1 = 0. Therefore, the value of the following algebraic formula is constant, A-B = - 1
3. (1) if a + B + C = 0, x = 1
(2) If A-B + C = 0, x = - 1
(3) If C = 0, x = 0 or x = - (B / a)
(4) If 4A + C = 2B, x = - 2

.. A quadratic equation of one variable. The product of two is C / A. what is the sum of two- B / a?

The product of two quadratic equations in one variable is C / A, and the sum of the two is - B / A

Use a simple method to solve the equation. Pay attention to the explanation In addition, I'll give you a quadratic formula to ask what makes sense. This should have a typical example (the most important)

First, simplify. After simplification, if a, B and C are very small, you can choose the matching method. If B happens to be 0, move the constant term and square it directly. If you can directly cross multiply, you can directly open the root. You can also decompose the formula first and solve the equation according to the method of decomposing the factor learned at the beginning. If none of the above methods work, you can use the formula method, That is, 2A / - B ± square b-4ac under the root sign. There is another way to draw the parabola of the univariate quadratic equation and look at the intersection with the x-axis. (I don't recommend it very much, although our teacher always emphasizes the combination of numbers and shapes.)
What does it mean? If it is to see whether there are real roots, it is very simple. First simplify it into a general form, and then calculate "b-square-4ac". If > 0, there are two unequal real roots. If = 0, there are two equal real roots. If < 0, there are no real roots, but there are increasing roots
Completely handwritten, I'm so tired. Please take a drop-down

How to express the product and sum of two quadratic equations of one variable with a, B and C

ax^2+bx+c=0 a(x-x1)(x-x2)=0 ax^2-a(x1+x2)+ax1x2=0 x1+x2=-b/a; x1x2=c/a

Why is the product of two quadratic equations of one variable C / A and the sum of two equations B / a Why is the product of two quadratic equations of one variable C / A and the sum of two equations - B / a

a*x^2+b*x+c=0
a(x-x1)(x-x2)=a*x^2+b*x+c
=a*x^2-a*(x1+x2)+a*x1*x2
Expand to get
x1+x2=-b/a
x1*x2=c/a

The sum of the coefficients of the univariate quadratic equation is equal to 0 and the ratio of the two is 1